Firebase android : make username unique

2018-12-31 04:16发布

Parse will shut down at the end of the year, so I decided to start using Firebase. I need to implement a register process with 3 fields : email, username, password (Email & username must be unique for my app).

Since, Firebase is not providing an easy way to manage username like Parse, I decided to use only the email/password registration and save some additional data like username. Here is my users data structure :

app : {
    users: {
       "some-user-uid": {
            email: "test@test.com"
            username: "myname"
       }
    }
}

But, what I want to do is to make the username unique and to check it before creating an account. These are my rules :

{
    "rules": {
        ".read": true,
        ".write": true,
        "users": {
            "$uid": {
                ".write": "auth !== null && auth.uid === $uid",
                ".read": "auth !== null && auth.provider === 'password'",
                "username": {".validate": "!root.child('users').child(newData.child('username').val()).exists()"}
            }
        }
   }
}

Thank you very much for your help

3条回答
美炸的是我
2楼-- · 2018-12-31 04:27

Part of the answer is to store an index of usernames, that you check against in your security rules:

app : {
    users: {
       "some-user-uid": {
            email: "test@test.com"
            username: "myname"
       }
    },
    usernames: {
        "myname": "some-user-uid"
    }
}

So the usernames node maps a username to a uid. It essentially reads as "username 'myname' is owned by 'some-user-uid'".

With this data structure, your security rules can check if there is already an entry for a given username:

"users": {
  "$uid": {
    ".write": "auth !== null && auth.uid === $uid",
    ".read": "auth !== null && auth.provider === 'password'",
    "username": {
      ".validate": "
        !root.child('usernames').child(newData.val()).exists() ||
        root.child('usernames').child(newData.val()).val() == $uid"
    }
  }
}

This validates that the username isn't claimed by anyone yet OR it is claimed by the current user.

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永恒的永恒
3楼-- · 2018-12-31 04:36

Save usernames as suggested by Frank but when you save usernames, use runTransaction function in Firebase to make sure that the username is not taken. This function is guaranteed by Firebase to be an atomic operation so you can be rest assured of no collision

firebaseRef.child("usernames").child(username).runTransaction(new Transaction.Handler() {
    @Override
    public Transaction.Result doTransaction(MutableData mutableData) {
        if (mutableData.getValue() == null) {
            mutableData.setValue(authData.getUid());
            return Transaction.success(mutableData);
        }

        return Transaction.abort();
    }

    @Override
    public void onComplete(FirebaseError firebaseError, boolean commited, DataSnapshot dataSnapshot) {
        if (commited) {
            // username saved
        } else {
            // username exists
        }
    }
});
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谁念西风独自凉
4楼-- · 2018-12-31 04:40

I dont know much about firebase security yet, but I may have solved the problem using Java. I have posted it below.

my data structure is

myapp
{
  users: {
          <unique generated-id>
          { username: "example.username" }
}
}


public boolean isUsernameExists(final String enteredUsername) {
        final Boolean[] isExist = {false};
        FBref.child("users").addValueEventListener(new ValueEventListener() {
            @Override
            public void onDataChange(DataSnapshot dataSnapshot) {
                for (DataSnapshot userSnapshot : dataSnapshot.getChildren()) {
                    String existingUsername = (String) userSnapshot.child("userName").getValue();
                    if (existingUsername.equals(enteredUsername)) {
                        isExist[0] = true;
                    }
                }
            }
            @Override
            public void onCancelled(FirebaseError firebaseError) {
                //some error thrown here
            }
        });
        return isExist[0];
    }
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