How to make URL/Phone-clickable UILabel?

Question

I want to create a clickable label on my app leading me to a Safari webpage. I also want the user to be able to phone the numbers only by clicking on them ?

Thanks for your advices

Answer 1

Use UITextView instead of UILabel and it has a property to convert your text to hyperlink.

Objective-C:

yourTextView.editable = NO;
yourTextView.dataDetectorTypes = UIDataDetectorTypeAll;

Swift:

yourTextView.editable = false; 
yourTextView.dataDetectorTypes = UIDataDetectorTypes.All;

This will detect links automatically.

See the documentation for details.

Answer 2

Swift 4.0 possible solution using UIButton

     phoneButton = UIButton(frame: CGRect(x: view.frame.width * 0, y: view.frame.height * 0.1, width: view.frame.width * 1, height: view.frame.height * 0.05))
     phoneButton.setTitle("333-333-3333", for: .normal )
     phoneButton.setTitleColor(UIColor(red: 0 / 255, green: 0 / 255, blue: 238 / 255, alpha: 1.0), for: .normal)
     phoneButton.addTarget(self, action: #selector(self.callPhone), for: .touchUpInside )

     @objc func callPhone(){

         UIApplication.shared.open(URL(string:"tel://3333333333")!, options: [:] , completionHandler: nil)


    }

Answer 3

If you want this to be handled by UILabel and not UITextView, you can make UILabel subclass, like this one:

class LinkedLabel: UILabel {

fileprivate let layoutManager = NSLayoutManager()
fileprivate let textContainer = NSTextContainer(size: CGSize.zero)
fileprivate var textStorage: NSTextStorage?


override init(frame aRect:CGRect){
    super.init(frame: aRect)
    self.initialize()
}

required init?(coder aDecoder: NSCoder) {
    super.init(coder: aDecoder)
    self.initialize()
}

func initialize(){

    let tap = UITapGestureRecognizer(target: self, action: #selector(LinkedLabel.handleTapOnLabel))
    self.isUserInteractionEnabled = true
    self.addGestureRecognizer(tap)
}

override var attributedText: NSAttributedString?{
    didSet{
        if let _attributedText = attributedText{
            self.textStorage = NSTextStorage(attributedString: _attributedText)

            self.layoutManager.addTextContainer(self.textContainer)
            self.textStorage?.addLayoutManager(self.layoutManager)

            self.textContainer.lineFragmentPadding = 0.0;
            self.textContainer.lineBreakMode = self.lineBreakMode;
            self.textContainer.maximumNumberOfLines = self.numberOfLines;
        }

    }
}

func handleTapOnLabel(tapGesture:UITapGestureRecognizer){

    let locationOfTouchInLabel = tapGesture.location(in: tapGesture.view)
    let labelSize = tapGesture.view?.bounds.size
    let textBoundingBox = self.layoutManager.usedRect(for: self.textContainer)
    let textContainerOffset = CGPoint(x: ((labelSize?.width)! - textBoundingBox.size.width) * 0.5 - textBoundingBox.origin.x, y: ((labelSize?.height)! - textBoundingBox.size.height) * 0.5 - textBoundingBox.origin.y)

    let locationOfTouchInTextContainer = CGPoint(x: locationOfTouchInLabel.x - textContainerOffset.x, y: locationOfTouchInLabel.y - textContainerOffset.y)
    let indexOfCharacter = self.layoutManager.characterIndex(for: locationOfTouchInTextContainer, in: self.textContainer, fractionOfDistanceBetweenInsertionPoints: nil)


    self.attributedText?.enumerateAttribute(NSLinkAttributeName, in: NSMakeRange(0, (self.attributedText?.length)!), options: NSAttributedString.EnumerationOptions(rawValue: UInt(0)), using:{
        (attrs: Any?, range: NSRange, stop: UnsafeMutablePointer<ObjCBool>) in

        if NSLocationInRange(indexOfCharacter, range){
            if let _attrs = attrs{

                UIApplication.shared.openURL(URL(string: _attrs as! String)!)
            }
        }
    })

}}

This class was made by reusing code from this answer. In order to make attributed strings check out this answer. And here you can find how to make phone urls.

Answer 4

You can make custom UIButton and setText what ever u want and add method with that.

    UIButton *sampleButton = [UIButton buttonWithType:UIButtonTypeCustom];
    [sampleButton setFrame:CGRectMake(kLeftMargin, 10, self.view.bounds.size.width - kLeftMargin - kRightMargin, 52)];
    [sampleButton setTitle:@"URL Text" forState:UIControlStateNormal];
    [sampleButton setFont:[UIFont boldSystemFontOfSize:20]];

    [sampleButton addTarget:self action:@selector(buttonPressed) forControlEvents:UIControlEventTouchUpInside];
    [self.view addSubview:sampleButton];

-(void)buttonPressed:(id)sender{
 // open url

}

Answer 5

You can use a UITextView and select Detection for Links, Phone Numbers and other things in the inspector.

Answer 6

extension UITapGestureRecognizer {

    func didTapAttributedTextInLabel(label: UILabel, inRange targetRange: NSRange) -> Bool {

        let layoutManager = NSLayoutManager()
        let textContainer = NSTextContainer(size: CGSize.zero)
        let textStorage = NSTextStorage(attributedString: label.attributedText!)

        // Configure layoutManager and textStorage
        layoutManager.addTextContainer(textContainer)
        textStorage.addLayoutManager(layoutManager)

        // Configure textContainer
        textContainer.lineFragmentPadding = 0.0
        textContainer.lineBreakMode = label.lineBreakMode
        textContainer.maximumNumberOfLines = label.numberOfLines
        textContainer.size = label.bounds.size

        // main code
        let locationOfTouchInLabel = self.location(in: label)

        let indexOfCharacter = layoutManager.characterIndex(for: locationOfTouchInLabel, in: textContainer, fractionOfDistanceBetweenInsertionPoints: nil)
        let indexOfCharacterRange = NSRange(location: indexOfCharacter, length: 1)
        let indexOfCharacterRect = layoutManager.boundingRect(forGlyphRange: indexOfCharacterRange, in: textContainer)
        let deltaOffsetCharacter = indexOfCharacterRect.origin.x + indexOfCharacterRect.size.width

        if locationOfTouchInLabel.x > deltaOffsetCharacter {
            return false
        } else {
            return NSLocationInRange(indexOfCharacter, targetRange)
        }
    }
}