how to get selected row value in the KendoUI

2019-01-30 03:08发布

I have a kendoUI grid.

                @(Html.Kendo().Grid<EntityVM>()
                    .Name("EntitesGrid")
                                .HtmlAttributes(new { style = "height:750px;width:100%;scrollbar-face-color: #eff7fc;" })
                    .Columns(columns =>
                    {
                        columns.Bound(e => e.Id).Hidden().IncludeInMenu(false);
                        columns.Bound(e => e.EntityVersionId).Hidden().IncludeInMenu(false);
                        columns.Bound(e => e.Name).Width("70%").Title("Entity Name");
                        columns.Bound(e => e.EIN).Width("30%");
                    })
        .ToolBar(toolBar => toolBar.Template("<a class='k-button k-button-icontext k-grid-add' id='addEntity'><span class='k-icon k-add'></span>Entity</a>" +
             "<a class='k-button k-button-icontext' id='editEntity'><span class='k-icon k-edit'></span>Edit</a>"))
                    .DataSource(dataSource => dataSource
                    .Ajax().ServerOperation(false)
                    .Model(model => model.Id(e => e.Id))
                    .Read(read => read.Action("GetEntities", "Entity", new { projectId = Request.QueryString[DataKeyNameConstants.ProjectId] })))
                    .Sortable()
                    .Scrollable()
                    .Filterable()
                    .Resizable(resize => resize.Columns(true))
                    .Reorderable(reorder => reorder.Columns(true))
                    .ColumnMenu()
                    .Selectable(s => s.Mode(GridSelectionMode.Multiple))
                    .Events(events => events.Change("entSelChange"))
            )

now, I need to get the value of EntityVersionId from the selected Row. but not sure how to do it.

here's my javascript function

$("#editEntity").click(function () {

    var entityGrid = $("#EntitesGrid").data("kendoGrid");

    // what should I do from here
});

UPDATE: add code to loop all rows.

function loadPreviousEntityVersion() {

    alert("sdfsdfsdf");
    var entityGrid = $("#EntitesGrid").data("kendoGrid");
    var data = entityGrid.dataSource.data();

    for(var i = 0; i<data.length; i++) {
        var currentDataItem = data[i];
        alert(dataItem.EntityVersionId);

    }
}

标签: grid kendo-ui
4条回答
萌系小妹纸
2楼-- · 2019-01-30 03:27

There is better way. I'm using it in pages where I'm using kendo angularJS directives and grids has'nt IDs...

change: function (e) {
   var selectedDataItem = e != null ? e.sender.dataItem(e.sender.select()) : null;
}
查看更多
仙女界的扛把子
3楼-- · 2019-01-30 03:34

If you want to select particular element use below code

var gridRowData = $("<your grid name>").data("kendoGrid");
var selectedItem = gridRowData.dataItem(gridRowData.select());
var quote = selectedItem["<column name>"];
查看更多
劫难
4楼-- · 2019-01-30 03:35

I think it needs to be checked if any row is selected or not? The below code would check it:

var entityGrid = $("#EntitesGrid").data("kendoGrid");
            var selectedItem = entityGrid.dataItem(entityGrid.select());
            if (selectedItem != undefined)
                alert("The Row Is SELECTED");
            else
                alert("NO Row Is SELECTED")
查看更多
地球回转人心会变
5楼-- · 2019-01-30 03:43

One way is to use the Grid's select() and dataItem() methods.

In single selection case, select() will return a single row which can be passed to dataItem()

var entityGrid = $("#EntitesGrid").data("kendoGrid");
var selectedItem = entityGrid.dataItem(entityGrid.select());
// selectedItem has EntityVersionId and the rest of your model

For multiple row selection select() will return an array of rows. You can then iterate through the array and the individual rows can be passed into the grid's dataItem().

var entityGrid = $("#EntitesGrid").data("kendoGrid");
var rows = entityGrid.select();
rows.each(function(index, row) {
  var selectedItem = entityGrid.dataItem(row);
  // selectedItem has EntityVersionId and the rest of your model
});
查看更多
登录 后发表回答