How to update std::map after using the find method

2019-01-30 01:30发布

How to update the value of a key in std::map after using the find method?

I have a map and iterator declaration like this:

map <char, int> m1;
map <char, int>::iterator m1_it;
typedef pair <char, int> count_pair;

I'm using the map to store the number of occurrences of a character.

I'm using Visual C++ 2010.

标签: c++ map stl stdmap
4条回答
Summer. ? 凉城
2楼-- · 2019-01-30 01:47

std::map::find returns an iterator to the found element (or to the end() if the element was not found). So long as the map is not const, you can modify the element pointed to by the iterator:

std::map<char, int> m;
m.insert(std::make_pair('c', 0));  // c is for cookie

std::map<char, int>::iterator it = m.find('c'); 
if (it != m.end())
    it->second = 42;
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Viruses.
3楼-- · 2019-01-30 01:47

You can also do like this-

 std::map<char, int>::iterator it = m.find('c'); 
 if (it != m.end())
 (*it).second = 42;
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混吃等死
4楼-- · 2019-01-30 01:56

I would use the operator[].

map <char, int> m1;

m1['G'] ++;  // If the element 'G' does not exist then it is created and 
             // initialized to zero. A reference to the internal value
             // is returned. so that the ++ operator can be applied.

// If 'G' did not exist it now exist and is 1.
// If 'G' had a value of 'n' it now has a value of 'n+1'

So using this technique it becomes really easy to read all the character from a stream and count them:

map <char, int>                m1;
std::ifstream                  file("Plop");
std::istreambuf_iterator<char> end;

for(std::istreambuf_iterator<char> loop(file); loop != end; ++loop)
{
    ++m1[*loop]; // prefer prefix increment out of habbit
}
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地球回转人心会变
5楼-- · 2019-01-30 02:06

You can use std::map::at member function, it returns a reference to the mapped value of the element identified with key k.

std::map<char,int> mymap = {
                               { 'a', 0 },
                               { 'b', 0 },
                           };

  mymap.at('a') = 10;
  mymap.at('b') = 20;
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