Tkinter Python GUI Issues

Question

Below is my code, it runs but I'm not sure how to get the "Run text" button to prompt me to open text file in new window, currently a new window appears with a "Quit" button, nothing else.

import tkFileDialog
import Tkinter as tk
from Tkinter import *
import logging

 logging.basicConfig(filename= "log_file.txt", filemode = "w", level=logging.DEBUG, format='%(asctime)s %(message)s', datefmt='%d/%m/%Y %I:%M:%S %p')

logging.warning('is when this event was logged.')

class HomeScreen:
def __init__(self, master):
    self.master = master
    self.frame = tk.Frame(self.master)
    self.button1 = tk.Button(self.frame, text = 'Run Text', width = 25, command = self.new_window)
    self.button1.pack()
    self.frame.pack()

def openFile(self):
    openfile = tkFileDialog.askopenfile().read()
    text= open(openfile, 'r').read()
    T.insert(1.0, openfile)
    T = Text(height=10, width=100)
    T.pack()
    T.insert(END, "Select file to input")
    B = Button(root, text="Open", command=openFile)
    B.pack()
    mainloop()
    return

def new_window(self):
    self.newWindow = tk.Toplevel(self.master)
    self.app = Quit(self.newWindow)

class Quit:
def __init__(self, master):
    self.master = master
    self.frame = tk.Frame(self.master)
    self.quitButton = tk.Button(self.frame, text = 'Quit', width = 25, command = self.close_windows)
    self.quitButton.pack()
    self.frame.pack()
def close_windows(self):
    self.master.destroy()

def main(): 
root = tk.Tk()
app = HomeScreen(root)
app = Quit(root)
root.mainloop()

if __name__ == '__main__':
main()

I'm sure my code is very messy as I'm just a beginner, some parts may not be needed, any advice would be greatly appreciated.

Answer 1

If you want that "Run text" open's a file dialog change called method:

self.button1 = tk.Button(self.frame, text = 'Run Text', width = 25, command = self.openFile)

Answer 2

I've simplified your code a bit, but I've also enhanced it a little. I use askopenfilename rather than askopenfile, so we can get the file name and display it in the titlebar of each Toplevel window containing a Text widget.

import tkFileDialog
import Tkinter as tk

class HomeScreen:
    def __init__(self, master):
        self.master = master
        frame = tk.Frame(master)
        frame.pack()
        button = tk.Button(frame, text='Show Text', width=25, command=self.open_file)
        button.pack()
        button = tk.Button(frame, text='Quit', width=25, command=master.destroy)
        button.pack()
        master.mainloop()

    def open_file(self):
        filename = tkFileDialog.askopenfilename()
        if not filename:
            #User cancelled
            return
        with open(filename) as f:
            filedata = f.read()

        window = tk.Toplevel(self.master)
        window.title(filename)
        text = tk.Text(window, height=10, width=100)
        text.pack()
        text.insert(1.0, filedata)


def main():
    root = tk.Tk()
    HomeScreen(root)

if __name__ == '__main__':
    main()

---

To display the text file one word at a time you can replace the open_file method with the version below. You'll also need to add the show_word method. I'm not claiming that this is the best way to achieve this effect, but at least it works. :)

def show_word(self, word):
    self.text.delete(1.0, tk.END)
    self.text.insert(tk.END, word)

def open_file(self):
    filename = tkFileDialog.askopenfilename()
    if not filename:
        #User cancelled
        return
    with open(filename) as f:
        filedata = f.read()

    words = filedata.split()

    window = tk.Toplevel(self.master)
    window.title(filename)
    self.text = text = tk.Text(window, height=10, width=100)
    text.pack()

    delta = 1000    #in millseconds
    delay = 0
    for word in words:
        window.after(delay, lambda word=word: self.show_word(word))
        #print word
        delay += delta