I'm working on a generative art project where I would like to allow users to save the resulting images from an algorithm. The general idea is:
- Create an image on an HTML5 Canvas using a generative algorithm
- When the image is completed, allow users to save the canvas as an image file to the server
- Allow the user to either download the image or add it to a gallery of pieces of produced using the algorithm.
However, I’m stuck on the second step. After some help from Google, I found this blog post, which seemed to be exactly what I wanted:
Which led to the JavaScript code:
function saveImage() {
var canvasData = canvas.toDataURL("image/png");
var ajax = new XMLHttpRequest();
ajax.open("POST", "testSave.php", false);
ajax.onreadystatechange = function() {
console.log(ajax.responseText);
}
ajax.setRequestHeader("Content-Type", "application/upload");
ajax.send("imgData=" + canvasData);
}
and corresponding PHP (testSave.php):
<?php
if (isset($GLOBALS["HTTP_RAW_POST_DATA"])) {
$imageData = $GLOBALS['HTTP_RAW_POST_DATA'];
$filteredData = substr($imageData, strpos($imageData, ",") + 1);
$unencodedData = base64_decode($filteredData);
$fp = fopen('/path/to/file.png', 'wb');
fwrite($fp, $unencodedData);
fclose($fp);
}
?>
But this doesn’t seem to do anything at all.
More Googling turns up this blog post which is based off of the previous tutorial. Not very different, but perhaps worth a try:
$data = $_POST['imgData'];
$file = "/path/to/file.png";
$uri = substr($data,strpos($data, ",") + 1);
file_put_contents($file, base64_decode($uri));
echo $file;
This one creates a file (yay) but it’s corrupted and doesn’t seem to contain anything. It also appears to be empty (file size of 0).
Is there anything really obvious that I’m doing wrong? The path where I’m storing my file is writable, so that isn’t an issue, but nothing seems to be happening and I’m not really sure how to debug this.
Edit
Following Salvidor Dali’s link I changed the AJAX request to be:
function saveImage() {
var canvasData = canvas.toDataURL("image/png");
var xmlHttpReq = false;
if (window.XMLHttpRequest) {
ajax = new XMLHttpRequest();
}
else if (window.ActiveXObject) {
ajax = new ActiveXObject("Microsoft.XMLHTTP");
}
ajax.open("POST", "testSave.php", false);
ajax.setRequestHeader("Content-Type", "application/x-www-form-urlencoded");
ajax.onreadystatechange = function() {
console.log(ajax.responseText);
}
ajax.send("imgData=" + canvasData);
}
And now the image file is created and isn’t empty! It seems as if the content type matters and that changing it to x-www-form-urlencoded
allowed the image data to be sent.
The console returns the (rather large) string of base64 code and the datafile is ~140 kB. However, I still can’t open it and it seems to not be formatted as an image.
I think you should tranfer image in base64 to image with blob, because when you use base64 image, it take a lot of log lines or a lot of line will send to server. With blob, it only the file. You can use this code bellow:
And canvas code here:
After that you can use ajax with Form:
This code using CoffeeScript syntax.
Send canvas image to PHP:
Here's PHP script:
photo_upload.php
Here is an example how to achieve what you need:
1) Draw something (taken from canvas tutorial)
2) Convert canvas image to URL format (base64)
3) Send it to your server via Ajax
3) Save base64 on your server as an image (here is how to do this in PHP, the same ideas is in every language. Server side in PHP can be found here):
I've worked on something similar. Had to convert canvas Base64-encoded image to
Uint8Array Blob
.I played with this two weeks ago, it's very simple. The only problem is that all the tutorials just talk about saving the image locally. This is how I did it:
1) I set up a form so I can use a POST method.
2) When the user is done drawing, he can click the "Save" button.
3) When the button is clicked I take the image data and put it into a hidden field. After that I submit the form.
4) When the form is submited I have this small php script:
If you want to save data that is derived from a Javascript
canvas.toDataURL()
function, you have to convert blanks into plusses. If you do not do that, the decoded data is corrupted:http://php.net/manual/ro/function.base64-decode.php