I've got a database table mytable with a column name in Varchar format, and column date with Datetime values. I'd like to count names with certain parameters grouped by date. Here is what I do:
SELECT
CAST(t.date AS DATE) AS 'date',
COUNT(*) AS total,
SUM(LENGTH(LTRIM(RTRIM(t.name))) > 4
AND (LOWER(t.name) LIKE '%[a-z]%')) AS 'n'
FROM
mytable t
GROUP BY
CAST(t.date AS DATE)
It seems that there's something wrong with range syntax here, if I just do LIKE 'a%'
it does count properly all the fields starting with 'a'. However, the query above returns 0 for n, although should count all the fields containing at least one letter.
I believe you want to use WHERE REGEXP '^[a-z]$' instead of LIKE.
I believe LIKE is just for searching for parts of a string, but it sounds like you want to implement a regular expression to search for a range.
In that case, use REGEXP instead. For example (simplified):
Your current query is looking for a string of literally "[a-z]".
Updated:
You have regex in your LIKE statement, which doesn't work. You need to use RLIKE or REGEXP.
Also just FYI, MySQL is terrible with strings, so you really should trim before you insert into the database. That way you don't get all that crazy overhead everytime you want to select.
You write:
Indeed so. MySQL's LIKE operator (and SQL generally) does not support range notation, merely simple wildcards.
Try MySQL's nonstandard RLIKE (a.k.a. REGEXP), for fuller-featured pattern matching.