How to pass parameters in GET requests with jQuery

2019-01-03 01:35发布

How should I be passing query string values in a jQuery Ajax request? I currently do them as follows but I'm sure there is a cleaner way that does not require me to encode manually.

$.ajax({
    url: "ajax.aspx?ajaxid=4&UserID=" + UserID + "&EmailAddress=" + encodeURIComponent(EmailAddress),
    success: function(response) {
        //Do Something
    },
    error: function(xhr) {
        //Do Something to handle error
    }
});

I’ve seen examples where query string parameters are passed as an array but these examples I've seen don't use the $.ajax() model, instead they go straight to $.get(). For example:

$.get("ajax.aspx", { UserID: UserID , EmailAddress: EmailAddress } );

I prefer to use the $.ajax() format as it's what I’m used to (no particularly good reason - just a personal preference).

Edit 09/04/2013:

After my question was closed (as "Too Localised") i found a related (identical) question - with 3 upvotes no-less (My bad for not finding it in the first place):

Using jquery to make a POST, how to properly supply 'data' parameter?

This answered my question perfectly, I found that doing it this way is much easier to read & I don't need to manually use encodeURIComponent() in the URL or the DATA values (which is what i found unclear in bipen's answer). This is because the data value is encoded automatically via $.param()). Just in case this can be of use to anyone else, this is the example I went with:

$.ajax({
    url: "ajax.aspx?ajaxid=4",
    data: { 
        "VarA": VarA, 
        "VarB": VarB, 
        "VarC": VarC
    },
    cache: false,
    type: "POST",
    success: function(response) {

    },
    error: function(xhr) {

    }
});

8条回答
做个烂人
2楼-- · 2019-01-03 02:15

Put your params in the data part of the ajax call. See the docs. Like so:

$.ajax({
    url: "/TestPage.aspx",
    data: {"first": "Manu","Last":"Sharma"},
    success: function(response) {
        //Do Something
    },
    error: function(xhr) {
        //Do Something to handle error
    }
});
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Explosion°爆炸
3楼-- · 2019-01-03 02:23

The data parameter of ajax method allows you send data to server side.On server side you can request the data.See the code

var id=5;
$.ajax({
    type: "get",
    url: "url of server side script",
    data:{id:id},
    success: function(res){
        console.log(res);
    },
error:function(error)
{
console.log(error);
}
});

At server side receive it using $_GET variable.

$_GET['id'];
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趁早两清
4楼-- · 2019-01-03 02:27

You can use the $.ajax(), and if you don't want to put the parameters directly into the URL, use the data:. That's appended to the URL

Source: http://api.jquery.com/jQuery.ajax/

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兄弟一词,经得起流年.
5楼-- · 2019-01-03 02:27

Had the same problem where I specified data but the browser was sending requests to URL ending with [Object object].

You should have processData set to true.

processData: true, // You should comment this out if is false or set to true
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爷的心禁止访问
6楼-- · 2019-01-03 02:28

Try adding this:

$.ajax({
    url: "ajax.aspx",
    type:'get',
    data: {ajaxid:4, UserID: UserID , EmailAddress: encodeURIComponent(EmailAddress)},
    dataType: 'json',
    success: function(response) {
      //Do Something
    },
    error: function(xhr) {
    //Do Something to handle error
    }
});

Depends on what datatype is expected, you can assign html, json, script, xml

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Viruses.
7楼-- · 2019-01-03 02:29

Use data option of ajax. You can send data object to server by data option in ajax and the type which defines how you are sending it (either POST or GET). The default type is GET method

Try this

$.ajax({
  url: "ajax.aspx",
  type: "get", //send it through get method
  data: { 
    ajaxid: 4, 
    UserID: UserID, 
    EmailAddress: EmailAddress
  },
  success: function(response) {
    //Do Something
  },
  error: function(xhr) {
    //Do Something to handle error
  }
});

And you can get the data by (if you are using PHP)

 $_GET['ajaxid'] //gives 4
 $_GET['UserID'] //gives you the sent userid

In aspx, I believe it is (might be wrong)

 Request.QueryString["ajaxid"].ToString(); 
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