I am currently working on an Android application whereupon I programmatically write a shortcut to the home screen. Something like this:
Intent shortcutIntent = new Intent();
shortcutIntent.setClassName(ai.packageName, ai.name);
shortcutIntent.addFlags(Intent.FLAG_ACTIVITY_NEW_TASK);
shortcutIntent.addFlags(Intent.FLAG_ACTIVITY_CLEAR_TOP);
shortcutIntent.addCategory(Intent.ACTION_PICK_ACTIVITY);
Intent intent = new Intent();
intent.putExtra(Intent.EXTRA_SHORTCUT_INTENT, shortcutIntent);
intent.putExtra(Intent.EXTRA_SHORTCUT_NAME, appName);
BitmapDrawable bd=(BitmapDrawable)(res.get(app_id).activityInfo.loadIcon(p).getCurrent());
Bitmap newbit;
newbit=bd.getBitmap();
intent.putExtra(Intent.EXTRA_SHORTCUT_ICON, newbit);
intent.setAction("com.android.launcher.action.INSTALL_SHORTCUT");
context.sendBroadcast(intent);
(it was actually a StackOverflow post that pointed me to this solution).
Anyway, when I run the app in the emulator, the shortcut is written to the fifth page from the left(on 2.3 home screen ). A subsequent run writes the shortcut to the 4th page from the left on the home screen.
My question is this: is there a way to write the shortcut to the center page or the first page (like passing indexes for the 2-D array that seems to hold the app shortcuts)? am I missing something in the API?
Thanks!
You cannot decide where the shortcut will go.