Prolog map procedure that applies predicate to lis

2018-12-31 03:42发布

How do you write a Prolog procedure map(List, PredName, Result) that applies the predicate PredName(Arg, Res) to the elements of List, and returns the result in the list Result?

For example:

test(N,R) :- R is N*N.

?- map([3,5,-2], test, L).
L = [9,25,4] ;
no

1条回答
骚的不知所云
2楼-- · 2018-12-31 04:04

This is usually called maplist/3 and is part of the Prolog prologue. Note the different argument order!

:- meta_predicate maplist(2, ?, ?).

maplist(_C_2, [], []).
maplist( C_2, [X|Xs], [Y|Ys]) :-
   call(C_2, X, Y),
   maplist( C_2, Xs, Ys).

The different argument order permits you to easily nest several maplist-goals.

?- maplist(maplist(test),[[1,2],[3,4]],Rss).
Rss = [[1,4],[9,16]].

maplist comes in different arities and corresponds to the following constructs in functional languages, but requires that all lists are of same length. Note that Prolog does not have the asymmetry between zip/zipWith and unzip. A goal maplist(C_3, Xs, Ys, Zs) subsumes both and even offers more general uses.

  • maplist/2 corresponds to all
  • maplist/3 corresponds to map
  • maplist/4 corresponds to zipWith but also unzip
  • maplist/5 corresponds to zipWith3 and unzip3
  • ...
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