HttpServletRequest to complete URL

Question

I have an HttpServletRequest object.

How do I get the complete and exact URL that caused this call to arrive at my servlet?

Or at least as accurately as possible, as there are perhaps things that can be regenerated (the order of the parameters, perhaps).

Answer 1

In a Spring project you can use

UriComponentsBuilder.fromHttpRequest(new ServletServerHttpRequest(request)).build().toUriString()

Answer 2

You can use filter .

@Override
    public void doFilter(ServletRequest arg0, ServletResponse arg1, FilterChain arg2) throws IOException, ServletException {
            HttpServletRequest test1=    (HttpServletRequest) arg0;

         test1.getRequestURL()); it gives  http://localhost:8081/applicationName/menu/index.action
         test1.getRequestURI()); it gives applicationName/menu/index.action
         String pathname = test1.getServletPath()); it gives //menu/index.action


        if(pathname.equals("//menu/index.action")){ 
            arg2.doFilter(arg0, arg1); // call to urs servlet or frameowrk managed controller method


            // in resposne 
           HttpServletResponse httpResp = (HttpServletResponse) arg1;
           RequestDispatcher rd = arg0.getRequestDispatcher("another.jsp");     
           rd.forward(arg0, arg1);





    }

donot forget to put <dispatcher>FORWARD</dispatcher> in filter mapping in web.xml

Answer 3

Use the following methods on HttpServletRequest object

java.lang.String getRequestURI() -Returns the part of this request's URL from the protocol name up to the query string in the first line of the HTTP request.

java.lang.StringBuffer getRequestURL() -Reconstructs the URL the client used to make the request.

java.lang.String getQueryString() -Returns the query string that is contained in the request URL after the path.