How to change options of <select> with jQuer

2019-01-03 00:50发布

Suppose a list of options is available, how do you update the <select> with new <option>s?

9条回答
贪生不怕死
2楼-- · 2019-01-03 01:27

For some odd reason this part

$el.empty(); // remove old options

from CMS solution didn't work for me, so instead of that I've simply used this

el.html(' ');

And it's works. So my working code now looks like that:

var newOptions = {
    "Option 1":"option-1",
    "Option 2":"option-2"
};

var $el = $('.selectClass');
$el.html(' ');
$.each(newOptions, function(key, value) {
    $el.append($("<option></option>")
    .attr("value", value).text(key));
});
查看更多
啃猪蹄的小仙女
3楼-- · 2019-01-03 01:27

if we update <select> constantly and we need to save previous value :

var newOptions = {
    'Option 1':'value-1',
    'Option 2':'value-2'
};

var $el = $('#select');
var prevValue = $el.val();
$el.empty();
$.each(newOptions, function(key, value) {
   $el.append($('<option></option>').attr('value', value).text(key));
   if (value === prevValue){
       $el.val(value);
   }
});
$el.trigger('change');
查看更多
家丑人穷心不美
4楼-- · 2019-01-03 01:31

Old school of doing things by hand has always been good for me.

  1. Clean the select and leave the first option:

        $('#your_select_id').find('option').remove()
        .end().append('<option value="0">Selec...</option>')
        .val('whatever');
    
  2. If your data comes from a Json or whatever (just Concat the data):

        var JSONObject = JSON.parse(data);
        newOptionsSelect = '';
        for (var key in JSONObject) {
            if (JSONObject.hasOwnProperty(key)) {
                var newOptionsSelect = newOptionsSelect + '<option value="'+JSONObject[key]["value"]+'">'+JSONObject[key]["text"]+'</option>';
            }
        }
    
        $('#your_select_id').append( newOptionsSelect );
    
  3. My Json Objetc:

        [{"value":1,"text":"Text 1"},{"value":2,"text":"Text 2"},{"value":3,"text":"Text 3"}]
    

This solution is ideal for working with Ajax, and answers in Json from a database.

查看更多
登录 后发表回答