Python 3 : Sharing variables between methods in a

2019-01-26 19:52发布

Looking for how to make a variable set by one Method/function in a class accessible to another method/function in that same class without having to do excess (and problematic code) outside.

Here is an example that doesn't work, but may show you what I'm trying to do :

#I just coppied this one to have an init method
class TestClass(object):

    def current(self, test):
        """Just a method to get a value"""
        print(test)
        pass

    def next_one(self):
        """Trying to get a value from the 'current' method"""
        new_val = self.current_player.test
        print(new_val)
        pass

标签: python oop scope
2条回答
Anthone
2楼-- · 2019-01-26 20:19

You set it in one method and then look it up in another:

class TestClass(object):

    def current(self, test):
        """Just a method to get a value"""
        self.test = test
        print(test)

    def next_one(self):
        """Trying to get a value from the 'current' method"""
        new_val = self.test
        print(new_val)

As a note, you will want to set self.test before you try to retrieve it. Otherwise, it will cause an error. I generally do that in __init__:

class TestClass(object):

    def __init__(self):
        self.test = None

    def current(self, test):
        """Just a method to get a value"""
        self.test = test
        print(test)

    def next_one(self):
        """Trying to get a value from the 'current' method"""
        new_val = self.test
        print(new_val)
查看更多
3楼-- · 2019-01-26 20:33

Is this what you're trying to do?

#I just coppied this one to have an init method
class TestClass(object):

    def current(self, test):
        """Just a method to get a value"""
        print(test)
        self.value = test
        pass

    def next_one(self):
        """Trying to get a value from the 'current' method"""
        new_val = self.value
        print(new_val)
        pass

a = TestClass()
b = TestClass()
a.current(10)
b.current(5)
a.next_one()
b.next_one()
查看更多
登录 后发表回答