When I typed:
>>> astrd = 123
>>> import sys
>>> sys.getrefcount(astrd)
3
>>>
I am not getting where is astrd
used 3 times ?
When I typed:
>>> astrd = 123
>>> import sys
>>> sys.getrefcount(astrd)
3
>>>
I am not getting where is astrd
used 3 times ?
It's not
astrd
that is referenced three times, but the value123
.astrd
is simply a name for the (immutable) number 123, which can be referenced however many times. Additionally to that, small integers are usually shared:In the second assignment, no new integer is created, instead
j
is just a new name for the integer123
.However, given very large integers, this does not hold:
Shared integers are an implementation detail of CPython (among others). Since small integers are instantiated very often, sharing them saves a lot of memory. This is made possible by the fact that integers are immutable in the first place.
For the additional reference in the second example, cf. codeape's answer.
ints are implemented in a special way, they are cached and shared, that why you don't get 1.
And python, uses reference counted objects. astrd is itself a reference, so you actually get the number of references to the int '123'. Try with another (user-defined) type and you'll get 1.
From the getrefcount docstring:
The other two references means that python internally is holding two references to the object. Maybe the locals() and globals() dictionaries count as one reference each?
I think it counts the references to 123, try other examples, like
The refcount for 9802374987193847 fits codeape's answer.
This is probably because numbers are immutables. If you for example use a list, it will always be 2 (from a clean prompt that is).
Btw, I get 2 for 123 as well, perhaps your setup is somewhat different? Or it might be time related or so?