Best solution to wait for all ajax callbacks to be

2019-01-26 08:13发布

Imagine we have to sources to be requested by ajax. I want to perform some actions when all callbacks are triggered. How this can be done besides this approach:

(function($){
  var sources = ['http://source1.com', 'http://source2.com'],
  guard = 0, 
  someHandler = function() { 
    if (guard != sources.length) { return; }
    //do some actions
  };

  for (var idx in sources) {
    $.getJSON(sources[idx], function(){ guard++; someHandler(); })
  }
})(jQuery)

What I don't like here is that in this case I can't handle response failing (eg. I can't set timeout for response to come) and overall approach (I suppose there should be a way to use more power of functional programming here)

Any ideas?

Regards!

UPD: Thanks for solution with chaining callbacks. I found a good approach here:. this is what was proposed in comments:

(function hidenext(jq){
    jq.eq(0).fadeOut("fast", function(){
        (jq=jq.slice(1)).length && hidenext(jq);
    });
})($('div#bodyContent a'))

With a little bit of tweaking it can wait for the last callback.

Now I want to handle properly long running requests. Any clues?

4条回答
劫难
2楼-- · 2019-01-26 08:34

Maybe you could 'cascade' the downloads, so the callback of the first getJSON triggers download from the next source, and so on? Then in the last callback you have no sources left and can call your 'done' function.

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\"骚年 ilove
3楼-- · 2019-01-26 08:35

Duplicate of javascript: execute a bunch of asynchronous method with one callback

function createCallback(limit, fn){
    var finishedCalls = 0;
    return function(){
        if (++finishedCalls == limit){
             fn();
        }
    };
}


var callback = createCallback(4, function(){
    alert("woot!");
});


async1(callback);
async2(callback);
async3(callback);
async4(callback);
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我欲成王,谁敢阻挡
4楼-- · 2019-01-26 08:44

You can always use $.ajax with "async: false" in options and/or use proper callbacks (beforeSend, error, dataFilter, success and complete).

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▲ chillily
5楼-- · 2019-01-26 08:47

Maybe I am wrong - but the rule is: serialization of AJAX - one at a time So you HAVE to chain it - each response (call back function) must submit the next one in turn

*.onreadystatechange will give you control (a function that is) )when it is ready - here you can submit the next one in turn

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