Get time difference between two dates in seconds

2019-01-02 23:39发布

I'm trying to get a difference between two dates in seconds. The logic would be like this :

  • set an initial date which would be now;
  • set a final date which would be the initial date plus some amount of seconds in future ( let's say 15 for instance )
  • get the difference between those two ( the amount of seconds )

The reason why I'm doing it it with dates it's because the final date / time depends on some other variables and it's never the same ( it depends on how fast a user does something ) and I also store the initial date for other things.

I've been trying something like this :

var _initial = new Date(),
    _initial = _initial.setDate(_initial.getDate()),
    _final = new Date(_initial);
    _final = _final.setDate(_final.getDate() + 15 / 1000 * 60);

var dif = Math.round((_final - _initial) / (1000 * 60));

The thing is that I never get the right difference. I tried dividing by 24 * 60 which would leave me with the seconds, but I never get it right. So what is it wrong with my logic ? I might be making some stupid mistake as it's quite late, but it bothers me that I cannot get it to work :)

6条回答
别忘想泡老子
2楼-- · 2019-01-02 23:50

time difference between now and 10 minutes later using momentjs

let start_time = moment().format('YYYY-MM-DD HH:mm:ss');
let next_time = moment().add(10, 'm').format('YYYY-MM-DD HH:mm:ss');

let diff_milliseconds = Date.parse(next_time) - Date.parse(star_time);
let diff_seconds = diff_milliseconds * 1000;
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Explosion°爆炸
3楼-- · 2019-01-02 23:55

You can use new Date().getTime() for getting timestamps. Then you can calculate the difference between end and start and finally transform the timestamp which is ms into s.

const start = new Date().getTime();
const end = new Date().getTime();

const diff = end - start;
const seconds = Math.floor(diff / 1000 % 60);
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叼着烟拽天下
4楼-- · 2019-01-03 00:00

Below code will give the time difference in second.

    var date1 = new Date(); // current date
    var date2 = new Date("06/26/2018"); // mm/dd/yyyy format
    var timeDiff = Math.abs(date2.getTime() - date1.getTime()); // in miliseconds
    var timeDiffInSecond = Math.ceil(timeDiff / 1000); // in second

    alert(timeDiffInSecond );
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贼婆χ
5楼-- · 2019-01-03 00:03

The Code

var startDate = new Date();
// Do your operations
var endDate   = new Date();
var seconds = (endDate.getTime() - startDate.getTime()) / 1000;

Or even simpler (endDate - startDate) / 1000 as pointed out in the comments unless you're using typescript.


The explanation

You need to call the getTime() method for the Date objects, and then simply subtract them and divide by 1000 (since it's originally in milliseconds). As an extra, when you're calling the getDate() method, you're in fact getting the day of the month as an integer between 1 and 31 (not zero based) as opposed to the epoch time you'd get from calling the getTime() method, representing the number of milliseconds since January 1st 1970, 00:00


Rant

Depending on what your date related operations are, you might want to invest in integrating a library such as date.js or moment.js which make things so much easier for the developer, but that's just a matter of personal preference.

For example in moment.js we would do moment1.diff(moment2, "seconds") which is beautiful.


Useful docs for this answer

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劳资没心,怎么记你
6楼-- · 2019-01-03 00:09
<script type="text/javascript">
var _initial = '2015-05-21T10:17:28.593Z';
var fromTime = new Date(_initial);
var toTime = new Date();

var differenceTravel = toTime.getTime() - fromTime.getTime();
var seconds = Math.floor((differenceTravel) / (1000));
document.write('+ seconds +');
</script>
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叼着烟拽天下
7楼-- · 2019-01-03 00:14

try using dedicated functions from high level programming languages. JavaScript .getSeconds(); suits here:

var specifiedTime = new Date("November 02, 2017 06:00:00");
var specifiedTimeSeconds = specifiedTime.getSeconds(); 

var currentTime = new Date();
var currentTimeSeconds = currentTime.getSeconds(); 

alert(specifiedTimeSeconds-currentTimeSeconds);
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