group by and scale/normalize a column in r

2019-01-25 10:37发布

I have a dataframe that looks like this:

  Store Temperature Unemployment Sum_Sales
1     1       42.31        8.106   1643691
2     1       38.51        8.106   1641957
3     1       39.93        8.106   1611968
4     1       46.63        8.106   1409728
5     1       46.50        8.106   1554807
6     1       57.79        8.106   1439542

What I can't figure out in R is how to group by and apply. So for each store (grouped), I want to normalize/scale two columns (sum_sales and temperature).

Desired output that I want is the following:

  Store Temperature Unemployment Sum_Sales
1     1       1.000        8.106   1.00000
2     1       0.000        8.106   0.94533
3     1       0.374        8.106   0.00000
4     2       0.012        8.106   0.00000
5     2       0.000        8.106   1.00000
6     2       1.000        8.106   0.20550

Here is the normalizing function that I created:

 normalit<-function(m){
   (m - min(m))/(max(m)-min(m))
 }

I'm using the dply package and can't seem to figure out how to group by and apply that function to a column. I tried something like this and get an error:

df2 <- df %.%
  group_by('Store') %.%
  summarise(Temperature = normalit(Temperature), Sum_Sales = normalit(Sum_Sales)))

Any suggestions/help would be greatly appreciated. Thanks.

标签: r plyr dplyr
2条回答
等我变得足够好
2楼-- · 2019-01-25 10:54

Here's a data.table solution. I changed your example a bit to have two type of store.

df <- read.table(header=T,text="Store Temperature Unemployment Sum_Sales
1     1       42.31        8.106   1643691
2     1       38.51        8.106   1641957
3     1       39.93        8.106   1611968
4     2       46.63        8.106   1409728
5     2       46.50        8.106   1554807
6     2       57.79        8.106   1439542")

library(data.table)
DT <- as.data.table(df)
DT[,list(Temperature=normalit(Temperature),Sum_Sales=normalit(Sum_Sales)),
    by=list(Store,Unemployment)]
#    Store Unemployment Temperature Sum_Sales
# 1:     1        8.106  1.00000000 1.0000000
# 2:     1        8.106  0.00000000 0.9453393
# 3:     1        8.106  0.37368421 0.0000000
# 4:     2        8.106  0.01151461 0.0000000
# 5:     2        8.106  0.00000000 1.0000000
# 6:     2        8.106  1.00000000 0.2055018

Note that your normalization will have problems if there is only 1 row for a stoer.

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狗以群分
3楼-- · 2019-01-25 11:05

The issue is that you are using the wrong dplyr verb. Summarize will create one result per group per variable. What you want is mutate. Mutate changes variables and returns a result of the same length as the original. See http://cran.rstudio.com/web/packages/dplyr/vignettes/introduction.html. Below two approaches using dplyr:

df %>%
    group_by(Store) %>%
    mutate(Temperature = normalit(Temperature), Sum_Sales = normalit(Sum_Sales))

df %>%
    group_by(Store) %>%
    mutate_each(funs(normalit), Temperature, Sum_Sales)

Note: The Store variable is different between your data and desired result. I assumed that @jlhoward got the right data.

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