Execute a file with arguments in Python shell

Question

I would like to run a command in Python Shell to execute a file with an argument.

For example: execfile("abc.py") but how to add 2 arguments?

Answer 1

Besides subprocess.call, you can also use subprocess.Popen. Like the following

subprocess.Popen(['./script', arg1, arg2])

Answer 2

If you want to run the scripts in parallel and give them different arguments you can do like below.

import os
os.system("python script.py arg1 arg2 & python script.py arg11 arg22")

Answer 3

Actually, wouldn't we want to do this?

import sys
sys.argv = ['abc.py','arg1', 'arg2']
execfile('abc.py')

Answer 4

You can't pass command line arguments with execfile(). Look at subprocess instead.