I need to know how to be able to make a dialog pop-up when a user clicks a button.
I'm relatively new to both Python and PyQt/QtDesigner. I've only been using in them for about a month, but I think I have a good grasp.
Here's what I have: A main dialog (which is the main part of the application), which I designed in QtDesigner. I converted the .ui to .py using pyuic4easy.
Here's what I want to do: design a new dialog box in the QtDesigner and somehow make it pop up when a user clicks a button on the first (main) dialog.
Here's the code for my main dialog:
import sys
from PyQt4.QtCore import *
from loginScreen import *
class MyForm(QtGui.QDialog):
def __init__(self, parent=None):
QtGui.QWidget.__init__(self, parent)
self.ui = Ui_Dialog()
self.ui.setupUi(self)
QtCore.QObject.connect(self.ui.pushButton, QtCore.SIGNAL('clicked()'), self.popup)
...
... Some functions ...
def popup(self):
#Pop-up the new dialog
if __name__ == "__main__":
app = QtGui.QApplication(sys.argv)
myapp= MyForm()
myapp.show()
sys.exit(app.exec_())
So as you can see, I've connected the first button to a method named 'popup', which needs to be filled in with code to make my second window pop up. How do I go about doing this? Remember that I already have designed my second dialog in QtDesigner, and I don't need to create a new one.
Thanks for all the help!
Pretty much the same way you do it for your main window (
MyForm
).As usual, you write a wrapper class for your QtDesigner code for the second dialog (like you did with
MyForm
). Let's call itMyPopupDialog
. Then in yourpopup
method, you create an instance and then show your instance with eitherexec_()
orshow()
depending whether you want a modal or modeless dialog. (If you are not familiar with Modal/Modeless concept, you might refer to the documentation.)So the overall thing might look like this (with a couple of modifications):