How to sum in pandas by unique index in several co

Question

I have a pandas DataFrame which details online activities in terms of "clicks" during an user session. There are as many as 50,000 unique users, and the dataframe has around 1.5 million samples. Obviously most users have multiple records.

The four columns are a unique user id, the date when the user began the service "Registration", the date the user used the service "Session", the total number of clicks.

The organization of the dataframe is as follows:

User_ID    Registration  Session      clicks
2349876    2012-02-22    2014-04-24   2 
1987293    2011-02-01    2013-05-03   1 
2234214    2012-07-22    2014-01-22   7 
9874452    2010-12-22    2014-08-22   2 
...

(There is also an index above beginning with 0, but one could set User_ID as the index.)

I would like to aggregate the total number of clicks by the user since Registration date. The dataframe (or pandas Series object) would list User_ID and "Total_Number_Clicks".

User_ID    Total_Clicks
2349876    722 
1987293    341
2234214    220 
9874452    1405 
...

How does one do this in pandas? Is this done by .agg()? Each User_ID needs to be summed individually.

As there are 1.5 million records, does this scale?

Answer 1

The first thing to do is filter registrations dates that precede the registration date, then group on the User_ID and sum.

gb = (df[df.Session >= df.Registration]
      .groupby('User_ID')
      .clicks.agg({'Total_Clicks': np.sum}))

>>> gb
         Total_Clicks
User_ID              
1987293             1
2234214             7
2349876             2
9874452             2

For the use case you mentioned, I believe this is scalable. It always depends, of course, on your available memory.

Answer 2

IIUC you can use groupby, sum and reset_index:

print df
   User_ID Registration    Session  clicks
0  2349876   2012-02-22 2014-04-24       2
1  1987293   2011-02-01 2013-05-03       1
2  2234214   2012-07-22 2014-01-22       7
3  9874452   2010-12-22 2014-08-22       2

print df.groupby('User_ID')['clicks'].sum().reset_index()
   User_ID  clicks
0  1987293       1
1  2234214       7
2  2349876       2
3  9874452       2

If first column User_ID is index:

print df
        Registration    Session  clicks
User_ID                                
2349876   2012-02-22 2014-04-24       2
1987293   2011-02-01 2013-05-03       1
2234214   2012-07-22 2014-01-22       7
9874452   2010-12-22 2014-08-22       2

print df.groupby(level=0)['clicks'].sum().reset_index()
   User_ID  clicks
0  1987293       1
1  2234214       7
2  2349876       2
3  9874452       2

Or:

print df.groupby(df.index)['clicks'].sum().reset_index()
   User_ID  clicks
0  1987293       1
1  2234214       7
2  2349876       2
3  9874452       2

EDIT:

As Alexander pointed, you need filter data before groupby, if Session dates is less as Registration dates per User_ID:

print df
   User_ID Registration    Session  clicks
0  2349876   2012-02-22 2014-04-24       2
1  1987293   2011-02-01 2013-05-03       1
2  2234214   2012-07-22 2014-01-22       7
3  9874452   2010-12-22 2014-08-22       2

print df[df.Session >= df.Registration].groupby('User_ID')['clicks'].sum().reset_index()
   User_ID  clicks
0  1987293       1
1  2234214       7
2  2349876       2
3  9874452       2

I change 3. row of data for better sample:

print df
        Registration    Session  clicks
User_ID                                
2349876   2012-02-22 2014-04-24       2
1987293   2011-02-01 2013-05-03       1
2234214   2012-07-22 2012-01-22       7
9874452   2010-12-22 2014-08-22       2

print df.Session >= df.Registration
User_ID
2349876     True
1987293     True
2234214    False
9874452     True
dtype: bool

print df[df.Session >= df.Registration]
        Registration    Session  clicks
User_ID                                
2349876   2012-02-22 2014-04-24       2
1987293   2011-02-01 2013-05-03       1
9874452   2010-12-22 2014-08-22       2

df1 = df[df.Session >= df.Registration]
print df1.groupby(df1.index)['clicks'].sum().reset_index()
   User_ID  clicks
0  1987293       1
1  2349876       2
2  9874452       2

Answer 3

suppose your dataframe name is df, then do the following

df.groupby(['User_ID']).sum()[['User_ID','clicks']]