Php system() / exec() don't re

2019-01-24 20:06发布

For common commands like 'ls', exec() works fine, eg:

exec('ls',$output,$retval);
var_dump($output,$retval);
// $output contains an array of filenames, and retval === 0

But when trying to execute another program, I can't get the output:

exec('some_command --a_parameter',$output,$retval);
var_dump($output,$retval);
// $output contains an empty array, end $retval === 0

This command prints some lines when executing it directly from the command-line though. I know the command has been successful because of the results (some files updated, data added, etc), and yet I can't see the output.

Any ideas?

2条回答
虎瘦雄心在
2楼-- · 2019-01-24 20:30

All the output was being sent to httpd/error_log when for some * reason, when the application found a warning (something internal, not even fatal)

My solution: When there is no output, assume it failed. My apache logs are going to get dirty, but whatever.

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SAY GOODBYE
3楼-- · 2019-01-24 20:48

It sounds like the program is outputting its warnings to standard error rather than standard output. exec will only catch standard output. I don't know for certain that standard error is always sent to the apache error log, but it seems likely.

If you don't need compatibility with non-*nix systems, you can redirect standard error to standard output by appending 2>&1 to the command:

exec('some_command --option 2>&1', $output, $ret);

This should both make the warnings available to your php program and prevent unnecessary logging.

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