Can I use a URL as the source for imagecreatefromj

2019-01-24 09:10发布

I know it’s possible to use imagecreatefromjpeg(), imagecreatefrompng(), etc. with a URL as the ‘filename’ with fopen(), but I'm unable to enable the wrappers due to security issues. Is there a way to pass a URL to imagecreatefromX() without enabling them?

I’ve also tried using cURL, and that too is giving me problems:

$ch = curl_init();
curl_setopt($ch, CURLOPT_URL,"http://www.../image31.jpg"); //Actually complete URL to image
curl_setopt($ch, CURLOPT_RETURNTRANSFER, 1);
$data = curl_exec($ch);
curl_close($ch);

$image = imagecreatefromstring($data);
var_dump($image);

imagepng($image);
imagedestroy($image);

3条回答
我欲成王,谁敢阻挡
2楼-- · 2019-01-24 09:51

You could always download the image (e.g. with cURL) to a temporary file, and then load the image from that file.

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Root(大扎)
3楼-- · 2019-01-24 09:52

You can download the file using cURL then pipe the result into imagecreatefromstring.

Example:

    $ch = curl_init();
    curl_setopt($ch, CURLOPT_URL, $imageurl); 
    curl_setopt($ch, CURLOPT_RETURNTRANSFER, 1); // good edit, thanks!
    curl_setopt($ch, CURLOPT_BINARYTRANSFER, 1); // also, this seems wise considering output is image.
    $data = curl_exec($ch);
    curl_close($ch);

    $image = imagecreatefromstring($data);
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Fickle 薄情
4楼-- · 2019-01-24 09:56

You could even implement a cURL based stream wrapper for 'http' using stream_wrapper_register.

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