javascript functions are objects?

2019-01-24 07:24发布

I am struggling with a Javascript question for some time now and I was not able to find an explanation on the web. I guess it is because I do not enter the right keywords which might also be related to why I am struggling with this at all.

My basic assumption is that it is possible to alter objects:

> var x = {'n': 2};
> x['n']
2
> x['n'] = 3;
3

pheww that worked. But still (functions are objects, too):

> var addn = function(a) {
    var n = 2;
    return n + a;
}

> addn(3);
5
> addn['n'] = 3;
3
> addn(3);
5

This time I was not able to change 'n'. Is there a way to fix this while keeping the functional flavor? As opposed to going fully OO. A related question I have would be how to maintain dependencies of functions for the purpose of for example testing - again w/o going OO? Of cause I am looking for a solution but if possible I would also like to understand which mechanism in Javascript makes me struggling.

Cheers,

Mark

Disclaimer: By mentioning OO I do not intent to say anything against OO. And I do not intent to say anything against VI or Emacs either. If I somehow hurt your feelings please skip this one.

7条回答
Rolldiameter
2楼-- · 2019-01-24 07:58

It's best to forget completely about the traditional OO concept of "objects" in Javascript-land, and to think instead in terms of closures. I strongly recommend reading this tutorial by John Resig, the creator of jQuery.

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别忘想泡老子
3楼-- · 2019-01-24 08:01

If I understand your question correctly, you can give a name to your anonymous function and access the function object's properties through that:

var addn = function func(a) {
  return func.n + a;
};

addn['n'] = 3;
addn(3); // returns 6
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▲ chillily
4楼-- · 2019-01-24 08:02

Private variables in a function scope, and a property of an object are 2 very different things. var n inside that function is completely inaccessible from outside that function.

So after that code runs, addn.n == 3, but the different value set to var n is initialized every time the funciton runs. Due to the quirks of javascript, a function can't really access it own properties very easy. Instead this pattern would be better achieved by passing in an argument function(n, a)

Or use an object to achieve something similar.

var adder = {
  n: 0,
  addn: function(a) {
    return this.n + a;
  }
};

adder.n = 5;
adder.addn(2); // 7
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我想做一个坏孩纸
5楼-- · 2019-01-24 08:02

Since JavaScript has function scope, you can use a function to store the value of n like so:

var addn = (function(n) {
  return function(x) {
    n += x;
    return n;
  }
}(2);

addn(3) // 5
addn(3) // 8
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Melony?
6楼-- · 2019-01-24 08:02

First, you are not changing the function variable by doing this:

addn['n'] = 3;

The function you defined does not have any name (also known as "anonymous function"). You are simply assigning that function to a variable called addn. A variable does not have any property- it is simply a container (Unless the variable refers to an array). So addn['n'] returns nothing.

As user casablanca noted, you can name your function as func and then access (and modify) its properties as func.<propertyname>.

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我命由我不由天
7楼-- · 2019-01-24 08:11

Basically, everything in Javascript is an object. If you said

var a=3;
a['n']=4;

references to 'a' would still return 3, but a also has a member 'n' which has value 4. So when you say addn['n'] = 3 you are adding a new member to addn, and not affecting the function in any way.

I strongly recommmend reading How good c habits can encourage bad javascript habits. In describing all the things you can do wrong, it's a great intro to the way objects work in Javascript.

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