toResponse in jersey ExceptionMapper does not get

Question

So I'm building a web application, we are using JPA and Jersey to consume/produces JSON data.

I have a custom "EntityException" aswell as a custom "EntityExceptionMapper"

Here's the mapper:

  @Provider
public class EntityExceptionMapper implements ExceptionMapper<EntityException> {

    public EntityExceptionMapper() {
        System.out.println("Mapper created");
    }

    @Override
    public Response toResponse(EntityException e) {
        System.out.println("This doesnt print!");
        return Response.serverError().build();
    }
}

My Exception:

public class EntityException extends Exception implements Serializable{

  public EntityException(String message) {
      super(message);
      System.out.println("This prints...");
  }

}

And I'm calling it from a REST call:

@POST
@Path("/test")
@Produces(MediaType.APPLICATION_JSON)
public String test() throws EntityException{
    throw new EntityException("This needs to be send as response!!");
    //return "test";
}

My problem is that, when the above exception is thrown, I get in the constructor (prints: "This prints...") Edit: I also get the: "Mapper created!"

But my response is empty, and I don't get to the sys out of my toResponse method. This is really similar to the example on the jersey website:

https://jersey.java.net/nonav/documentation/1.12/jax-rs.html#d4e435

What am I missing??

Answer 1

I used spring to wire up jersey app and used @Component with @Provider.

When I moved to jersey v > 2.5, it stopped working.

I resolved this very issue by putting @Singleton annotation instead of @Component alongside @Provider, like this:

@Provider
@Singleton
public class EntityExceptionMapper implements ExceptionMapper<EntityException> {...

Answer 2

I have encountered the same issue while develop sample REST API. While creating REST API i have given base package name like org.manish.rest.message, I supposed to create every other packages under the base package like this

---

1. model - org.manish.rest.message.model
2. database - org.manish.rest.message.database
3. resource - org.manish.rest.message.resource

in web.xml init param was given like this

 <init-param>
            <param-name>jersey.config.server.provider.packages</param-name>
            <param-value>org.manish.rest.message</param-value>
 </init-param>

It means, i have registered my base package in web.xml, what ever package i will create under this; will be consider by JAX-RS based on my call and requirement. But when i created my exception package by mistake i put package name org.manish.rest.exception. Since this was not registered in web.xml so my complete exception class was not considered to handle exception by JAX-RS. As a correction, i have just modified my exception package name from org.manish.rest.exception to org.manish.rest.message.exception

After that i executed once in post man and i got expected result.

Hope this can solve your query.

Thanks Manish

Answer 3

I'm using the Jersey JdkHttpServerFactory, and I just had to add the ExceptionMapper class as a resource, just like my other controller resources:

import com.sun.net.httpserver.HttpServer;
import javax.ws.rs.core.UriBuilder;
import java.net.URI;
import java.util.HashSet;
import java.util.Set;
import org.glassfish.jersey.jdkhttp.JdkHttpServerFactory;
import org.glassfish.jersey.server.ResourceConfig;

// ...

Set<Class> resources = new HashSet<>();
// Add whatever other resource classes you have...

//--->>> Add the exception mapper <<<---
resources.add(EntityExceptionMapper.class);

ResourceConfig resources = new ResourceConfig(resources);
URI uri = UriBuilder.fromUri("http://localhost/").build();
HttpServer server = JdkHttpServerFactory.createHttpServer(uri, resources);

Answer 4

I also face the same issue.Just add the package name that have the ExceptionMappperHandler classes.

<web-app version="2.5" xmlns="http://java.sun.com/xml/ns/javaee" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xsi:schemaLocation="http://java.sun.com/xml/ns/javaee http://java.sun.com/xml/ns/javaee/web-app_2_5.xsd">
    <servlet>
        <servlet-name>Jersey Web Application</servlet-name>
        <servlet-class>org.glassfish.jersey.servlet.ServletContainer</servlet-class>
        <init-param>
            <param-name>jersey.config.server.provider.packages</param-name>
            <param-value>Service,Utilities.ExceptionMapper</param-value>
        </init-param>
        <load-on-startup>1</load-on-startup>
    </servlet>
    <servlet-mapping>
        <servlet-name>Jersey Web Application</servlet-name>
        <url-pattern>/*</url-pattern>
    </servlet-mapping>
</web-app>

Here,service contain all service classes and Utilities.ExceptionMapper contains all exceptionMapper. Hope its help

Answer 5

I had the same problem. I just had to modify the web.xml. Previously in my web.xml file param-value was com.two95.restful.resource I just changed to root package com.two95.restful. Then it started working like a charm with just the @Provider annotation.

<servlet>
    <servlet-name>Jersey Web Application</servlet-name>
    <servlet-class>org.glassfish.jersey.servlet.ServletContainer</servlet-class>
    <init-param>
        <param-name>jersey.config.server.provider.packages</param-name>
        <param-value>com.two95.restful</param-value>
    </init-param>
    <load-on-startup>1</load-on-startup>
</servlet>

Answer 6

I am using deployment agnostic application model so the following worked for me:

public class MyApplication extends Application {
    public Set<Class<?>> getClasses() {
        Set<Class<?>> s = new HashSet<Class<?>>();
        s.add(HelloWorldResource.class);

        /** you need to add ExceptionMapper class as well **/
        s.add(EntityExceptionMapper.class)
        return s;
    }
}