Javascript-Setting background image of a DIV via a

2019-01-23 02:36发布

I have the following HTML:

<div id="tab1" style="position:relative; background-image:url(buttons/off.png);
    <a href="javascript:ChangeBackgroundImageOfTab('tab1', 'on');">
        <img id="DivBtn1" name="DivBtn1" src="buttons/text.png" >
    </a>
</div>

and the following Javascript:

function ChangeBackgroungImageOfTab(tabName, imagePrefix)
{
    document.getElementById(tabName).style.background-image= 'url("buttons/" + imagePrefix + ".png")';
}

The issue arises when i try to set the tabs background image via a call to getElementByID - I do now know how to create a dynamic URL that uses the parameter that was passed in, along with some other hard coded values. In this case, we are swapping the OFF background image with the ON background image.

How can i do this? Is there some way to use a javascript variable, assign the full path to it, then send it into the call as the background image path?

2条回答
不美不萌又怎样
2楼-- · 2019-01-23 02:46

You need to concatenate your string.

document.getElementById(tabName).style.backgroundImage = 'url(buttons/' + imagePrefix + '.png)';

The way you had it, it's just making 1 long string and not actually interpreting imagePrefix.

I would even suggest creating the string separate:

function ChangeBackgroungImageOfTab(tabName, imagePrefix)
{
    var urlString = 'url(buttons/' + imagePrefix + '.png)';
    document.getElementById(tabName).style.backgroundImage =  urlString;
}

As mentioned by David Thomas below, you can ditch the double quotes in your string. Here is a little article to get a better idea of how strings and quotes/double quotes are related: http://www.quirksmode.org/js/strings.html

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乱世女痞
3楼-- · 2019-01-23 02:56

From what I know, the correct syntax is:

function ChangeBackgroungImageOfTab(tabName, imagePrefix)
{
    document.getElementById(tabName).style.backgroundImage = "url('buttons/" + imagePrefix + ".png')";
}

So basically, getElementById(tabName).backgroundImage and split the string like:

"cssInHere('and" + javascriptOutHere + "/cssAgain')";
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