JavaScript OR (||) variable assignment explanation

2019-01-02 21:44发布

Given this snippet of JavaScript...

var a;
var b = null;
var c = undefined;
var d = 4;
var e = 'five';

var f = a || b || c || d || e;

alert(f); // 4

Can someone please explain to me what this technique is called (my best guess is in the title of this question!)? And how/why it works exactly?

My understanding is that variable f will be assigned the nearest value (from left to right) of the first variable that has a value that isn't either null or undefined, but I've not managed to find much reference material about this technique and have seen it used a lot.

Also, is this technique specific to JavaScript? I know doing something similar in PHP would result in f having a true boolean value, rather than the value of d itself.

12条回答
余生请多指教
2楼-- · 2019-01-02 21:48

See short-circuit evaluation for the explanation. It's a common way of implementing these operators; it is not unique to JavaScript.

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高级女魔头
3楼-- · 2019-01-02 21:48

Return output first true value.

If all are false return last false value.

Example:-

  null || undefined || false || 0 || 'apple'  // Return apple
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情到深处是孤独
4楼-- · 2019-01-02 21:57

Javascript variables are not typed, so f can be assigned an integer value even though it's been assigned through boolean operators.

f is assigned the nearest value that is not equivalent to false. So 0, false, null, undefined, are all passed over:

alert(null || undefined || false || '' || 0 || 4 || 'bar'); // alerts '4'
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回忆,回不去的记忆
5楼-- · 2019-01-02 21:57

It will evaluate X and, if X is not null, the empty string, or 0 (logical false), then it will assign it to z. If X is null, the empty string, or 0 (logical false), then it will assign y to z.

var x = '';
var y = 'bob';
var z = x || y;
alert(z);

Will output 'bob';

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浅入江南
6楼-- · 2019-01-02 21:59

There isn't any magic to it. Boolean expressions like a || b || c || d are lazily evaluated. Interpeter looks for the value of a, it's undefined so it's false so it moves on, then it sees b which is null, which still gives false result so it moves on, then it sees c - same story. Finally it sees d and says 'huh, it's not null, so I have my result' and it assigns it to the final variable.

This trick will work in all dynamic languages that do lazy short-circuit evaluation of boolean expressions. In static languages it won't compile (type error). In languages that are eager in evaluating boolean expressions, it'll return logical value (i.e. true in this case).

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其实,你不懂
7楼-- · 2019-01-02 22:01

Javacript uses short-circuit evaluation for logical operators || and &&. However, it's different to other languages in that it returns the result of the last value that halted the execution, instead of a true, or false value.

The following values are considered falsy in JavaScript.

  • false
  • null
  • "" (empty string)
  • 0
  • Nan
  • undefined

Ignoring the operator precedence rules, and keeping things simple, the following examples show which value halted the evaluation, and gets returned as a result.

false || null || "" || 0 || NaN || "Hello" || undefined // "Hello"

The first 5 values upto NaN are falsy so they are all evaluated from left to right, until it meets the first truthy value - "Hello" which makes the entire expression true, so anything further up will not be evaluated, and "Hello" gets returned as a result of the expression. Similarly, in this case:

1 && [] && {} && true && "World" && null && 2010 // null

The first 5 values are all truthy and get evaluated until it meets the first falsy value (null) which makes the expression false, so 2010 isn't evaluated anymore, and null gets returned as a result of the expression.

The example you've given is making use of this property of JavaScript to perform an assignment. It can be used anywhere where you need to get the first truthy or falsy value among a set of values. This code below will assign the value "Hello" to b as it makes it easier to assign a default value, instead of doing if-else checks.

var a = false;
var b = a || "Hello";

You could call the below example an exploitation of this feature, and I believe it makes code harder to read.

var messages = 0;
var newMessagesText = "You have " + messages + " messages.";
var noNewMessagesText = "Sorry, you have no new messages.";
alert((messages && newMessagesText) || noNewMessagesText);

Inside the alert, we check if messages is falsy, and if yes, then evaluate and return noNewMessagesText, otherwise evaluate and return newMessagesText. Since it's falsy in this example, we halt at noNewMessagesText and alert "Sorry, you have no new messages.".

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