I'm trying to avoid nested observables by using forkjoin
. The current (nested) version looks like this:
this.http.get('https://testdb1.firebaseio.com/.json').map(res => res.json()).subscribe(data_changes => {
this.http.get('https://testdb2.firebaseio.com/.json').map(res => res.json()).subscribe(data_all => {
/* Do this once resolved */
this.platform.ready().then(() => {
this.storage.set('data_changes', data_changes);
this.storage.set('data_all', data_all);
document.getElementById("chart").innerHTML = "";
this.createChart();
});
});
},
err => {
this.platform.ready().then(() => {
console.log("server error 2");
document.getElementById("chart").innerHTML = "";
this.createChart();
});
});
}
I can rewrite the first part as:
Observable.forkJoin(
this.http.get('https://testdb1.firebaseio.com/.json').map((res: Response) => res.json()),
this.http.get('https://testdb2.firebaseio.com/.json').map((res: Response) => res.json())
)
But i'm not sure how I would then add the .subscribe
method to access both data_changes
and data_all
.
Looking at another example, I know it should look something like .subscribe(res => this.combined = {friends:res[0].friends, customer:res[1]});
, but i'm not sure how to adapt this to my example.
Try to use
combineLatest
instead offorkJoin
:With
combineLatest
:You can also handle it by forkJoin , but forkJoin will return data when all calls are finished and return result , but in combineLatest When any observable emits a value, emit the latest value from each.
With
forkJoin
:Call both and check the console log , you will get idea.