JavaScript expression to generate a 5-digit number

2019-01-22 17:13发布

for my selenium tests I need an value provider to get a 5-digit number in every case. The problem with javascript is that the api of Math.random only supports the generation of an 0. starting float. So it has to be between 10000 and 99999.

So it would be easy if it would only generates 0.10000 and higher, but it also generates 0.01000. So this approach doesn't succeed:

Math.floor(Math.random()*100000+1)

Is it possible to generate a 5-digit number in every case (in an expression!) ?

4条回答
姐就是有狂的资本
2楼-- · 2019-01-22 17:24

if you want to generate say a zipcode, and don't mind leading zeros as long as it's 5 digits you can use:

(""+Math.random()).substring(2,7)
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三岁会撩人
3楼-- · 2019-01-22 17:31

You can get a random integer inclusive of any given min and max numbers using the following function:

function getRandomIntInclusive(min, max) {
  min = Math.ceil(min);
  max = Math.floor(max);
  return Math.floor(Math.random() * (max - min + 1)) + min;
}

For more examples and other use cases, checkout the Math.random MDN documentation.

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你好瞎i
4楼-- · 2019-01-22 17:33

Yes, you can create random numbers in any given range:

var min = 10000;
var max = 99999;
var num = Math.floor(Math.random() * (max - min + 1)) + min;

Or simplified:

var num = Math.floor(Math.random() * 90000) + 10000;
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欢心
5楼-- · 2019-01-22 17:35

What about:

Math.floor(Math.random()*90000) + 10000;
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