How can I return a 404/50x status code from a Grai

2019-01-22 16:55发布

I have a controller that needs to return a 404 page and status code on certain conditions. I can't seem to find out how to do this in Grails. A coworker recommended this method:

response.sendError(HttpServletResponse.SC_NOT_FOUND)

which works perfectly fine, but it's not very Grails-like. I know Rails' render method take a status argument, but Grails' render has no such functionality. Is there something I'm missing, what's the best way to accomplish this?

4条回答
男人必须洒脱
2楼-- · 2019-01-22 17:21

response.sendError(404) will work with Grails UrlMappings whereas response.status = 404 does not for some reason. This is useful if you want to render a custom 404 error page, as opposed to just sending 404 back to the browser.

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萌系小妹纸
3楼-- · 2019-01-22 17:26

Setting the response status with its own statement is good enough. It doesn't look too ugly and is pretty straightforward:

response.status = 404;

I've used this successfully myself and have seen others do it this way too. Since it's just a setter, you can also do other stuff after setting the status. Whichever status you set last will be what the HttpServletResponse uses when it actually sends the response back to the client.

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贪生不怕死
4楼-- · 2019-01-22 17:26

response.sendError and response.setStatus are the only two ways I know of. If you static import HttpServletResponse, then it's not that 'un-grails-like'.

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闹够了就滚
5楼-- · 2019-01-22 17:27

I don't know what version this started in, but in Grails 2.2.1 you can do:

render(status: 503, text: 'Failed to do stuff.')

http://grails.org/doc/2.2.1/ref/Controllers/render.html

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