What does the arrow operator, '->', do in

Question

While hunting through some code I came across the arrow operator, what exactly does it do? I thought Java did not have an arrow operator.

return (Collection<Car>) CollectionUtils.select(listOfCars, (arg0) -> {
        return Car.SEDAN == ((Car)arg0).getStyle();
});

Details: Java 6, Apache Commons Collection, IntelliJ 12

Update/Answer: It turns out that IntelliJ 12 supports Java 8, which supports lambdas, and is "folding" Predicates and displaying them as lambdas. Below is the "un-folded" code.

return (Collection<Car>) CollectionUtils.select(listOfCars, new Predicate() {
    public boolean evaluate(Object arg0) {
        return Car.SEDAN == ((Car)arg0).getStyle();
    }
});

Answer 1

This one is useful as well when you want to implement an interface

Runnable r = ()-> System.out.print("Run method");

is equivalent to

Runnable r = new Runnable() {
            @Override
            public void run() {
                System.out.print("Run method");
            }
        };

Answer 2

It's a lambda expression.

It means that, from the listOfCars, arg0 is one of the items of that list. With that item he is going to do, hence the ->, whatever is inside of the brackets.

In this example, he's going to return a list of cars that fit the condition

Car.SEDAN == ((Car)arg0).getStyle();

Answer 3

That's part of the syntax of the new lambda expressions, to be introduced in Java 8. There are a couple of online tutorials to get the hang of it, here's a link to one. Basically, the -> separates the parameters (left-side) from the actual expression (right side).

Answer 4

I believe, this arrow exists because of your IDE. IntelliJ IDEA does such thing with some code. This is called code folding. You can click at the arrow to expand it.