What is the best way of cloning/copying an observa

2019-01-21 21:47发布

Question says it all really. I want to copy an observable array to another in KnockoutJS.

标签: knockout.js
4条回答
劳资没心,怎么记你
2楼-- · 2019-01-21 21:59

I was faced with the same task; to clone an observable array. The only way I could figure out how to do it, is to convert the observable to an JS object, then convert that object to an observable object. The following function requires KnockoutJS mapping plugin: http://knockoutjs.com/documentation/plugins-mapping.html

function cloneObservable(observableObject) {
    return ko.mapping.fromJS(ko.toJS(observableObject));
}

Hope this helps

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一纸荒年 Trace。
3楼-- · 2019-01-21 22:15

Assuming you have something like:

modelA { someValues: observableArray(); }
modelB { iWantYourValues: observableArray(); }

You should be able to:

modelB.iWantYourValues(modelA.someValues())
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疯言疯语
4楼-- · 2019-01-21 22:22

To clone an observableArray you would want to do:

var viewModel = {
    array1: ko.observableArray(["one", "two"]),
    array2: ko.observableArray()
};

viewModel.clone = function() {
   viewModel.array1(viewModel.array2.slice(0));
};

If you want to just do a copy, then you would do:

viewModel.array1(viewModel.array2());

The problem with the second example is that the underlying array is the same, so pushing to array1 or array2 would result in both having the new value (as they both point to the same array).

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放荡不羁爱自由
5楼-- · 2019-01-21 22:22

Not exactly what you're asking, but I'd like to add this for posterity...

If you want to clone an observable that stays in sync with the original (most often to create a throttled/debounced clone while maintaining the original), you can do something as such:

const clone = ko.pureComputed(() => original()).extend({ rateLimit: 500 })

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