SQL Server 2008: delete duplicate rows

Question

I have duplicate rows in my table, how can I delete them based on a single column's value?

Eg

uniqueid, col2, col3 ...
1, john, simpson
2, sally, roberts
1, johnny, simpson

delete any duplicate uniqueIds
to get 

1, John, Simpson
2, Sally, Roberts

Answer 1

You probably have a row id that is assigned by the DB upon insertion and is actually unique. I'll call this rowId in my example.

rowId |uniqueid |col2  |col3
----- |-------- |----  |----
1      10        john   simpson
2      20        sally  roberts
3      10        johnny simpson

You can remove duplicates by grouping on the thing that is supposed to be unique (whether it be one column or many), then you grab a rowId from each group, and delete everything else besides those rowIds. In the inner query, everything in the table will have a rowId except for the duplicate rows.

select * 
--DELETE 
FROM MyTable 
WHERE rowId NOT IN 
(SELECT MIN(rowId) 
 FROM MyTable 
 GROUP BY uniqueid);

You could also use MAX instead of MIN with similar results.

Answer 2

Here is simple magic to remove duplicates

select * into NewTable from ExistingTable
union
select * from ExistingTable;

Answer 3

You can DELETE from a cte:

WITH cte AS (SELECT *,ROW_NUMBER() OVER(PARTITION BY uniqueid ORDER BY col2)'RowRank'
             FROM Table)
DELETE FROM cte 
WHERE RowRank > 1

The ROW_NUMBER() function assigns a number to each row. PARTITION BY is used to start the numbering over for each item in that group, in this case each value of uniqueid will start numbering at 1 and go up from there. ORDER BY determines which order the numbers go in. Since each uniqueid gets numbered starting at 1, any record with a ROW_NUMBER() greater than 1 has a duplicate uniqueid

To get an understanding of how the ROW_NUMBER() function works, just try it out:

SELECT *,ROW_NUMBER() OVER(PARTITION BY uniqueid ORDER BY col2)'RowRank'
FROM Table
ORDER BY uniqueid

You can adjust the logic of the ROW_NUMBER() function to adjust which record you'll keep or remove.

For instance, perhaps you'd like to do this in multiple steps, first deleting records with the same last name but different first names, you could add last name to the PARTITION BY:

WITH cte AS (SELECT *,ROW_NUMBER() OVER(PARTITION BY uniqueid, col3 ORDER BY col2)'RowRank'
             FROM Table)
DELETE FROM cte 
WHERE RowRank > 1

Answer 4

DECLARE @du TABLE (
    id INT,  
    Name VARCHAR(4)
)

INSERT INTO @du VALUES(1,'john')
INSERT INTO @du VALUES(2,'jane')
INSERT INTO @du VALUES(1,'john')

;WITH dup (id,dp)
AS
(SELECT id
, ROW_NUMBER() OVER(PARTITION BY id ORDER BY Name) AS dp
FROM @du)
DELETE FROM dup
WHERE dp > 1

SELECT *
FROM @du

Answer 5

You have many ways for deleting the duplicate records some of them are below...........

Different ways to delete Duplicate records

Using Row_Number() function and CTE

  with CTE(DuplicateCount) as  ( SELECT  ROW_NUMBER() OVER
(PARTITION by UniqueId order by UniqueId ) as DuplicateCount from
Table1 ) Delete from CTE where DuplicateCount > 1

  .Without using CTE*

Delete DuplicateCount from ( Select Row_Number() over(Partition by
UniqueId order by UniqueId) as Dup from Table1 ) DuplicateCount 
where DuplicateCount.Dup > 1

 .Without using row_Number() and CTE

Delete from Subject where RowId not in(select Min(RowId ) from
Subject group by UniqueId)

Answer 6

DELETE FROM table WHERE uniqueid='1' AND col2='john' Or you change col2='john' to col2='johnny'. Depends on which record you want to delete.

How did you end up with two same "unique" IDs in the first place?