How do I remove a substring from the end of a stri

Question

I have the following code:

url = 'abcdc.com'
print(url.strip('.com'))

I expected: abcdc

I got: abcd

Now I do

url.rsplit('.com', 1)

Is there a better way?

Answer 1

url.rsplit('.com', 1)

is not quite right.

What you actually would need to write is

url.rsplit('.com', 1)[0]

, and it looks pretty succinct IMHO.

However, my personal preference is this option because it uses only one parameter:

url.rpartition('.com')[0]

Answer 2

In one line:

text if not text.endswith(suffix) or len(suffix) == 0 else text[:-len(suffix)]

Answer 3

Since it seems like nobody has pointed this on out yet:

url = "www.example.com"
new_url = url[:url.rfind(".")]

This should be more efficient than the methods using split() as no new list object is created, and this solution works for strings with several dots.

Answer 4

import re

def rm_suffix(url = 'abcdc.com', suffix='\.com'):
    return(re.sub(suffix+'$', '', url))

I want to repeat this answer as the most expressive way to do it. Of course, the following would take less CPU time

def rm_dotcom(url = 'abcdc.com'):
    return(url[:-4] if url.endswith('.com') else url)

However, if CPU is the bottle neck why write in Python?

When is CPU a bottle neck anyway?? in drivers , maybe.

The advantages of using regular expression is code reusability. What if you next want to remove '.me' , which only has three characters?

Same code would do the trick.

>>> rm_sub('abcdc.me','.me')
'abcdc'

Answer 5

def remove_file_type(infile):
import re
return(re.sub('\.[^.]*$','',infile))
remove_file_type('abc.efg')'abc'

Answer 6

strip doesn't mean "remove this substring". x.strip(y) treats y as a set of characters and strips any characters in that set from the ends of x.

Instead, you could use endswith and slicing:

url = 'abcdc.com'
if url.endswith('.com'):
    url = url[:-4]

Or using regular expressions:

import re
url = 'abcdc.com'
url = re.sub('\.com$', '', url)