How to check if bootstrap modal is open, so i can

Question

i need to make a validation only if a modal is open, because if i open it, and then i close it, and the i press the button that opens the modal it doesn't work because it is making the jquery validation, but not showing because the modal was dismissed.

So i want to ad a jquery if modal is open so the i do validate, is this possible?

<script>
$(document).ready(function(){

var validator =$('#form1').validate(
 {
  ignore: "",
  rules: {

usu_login: {
  required: true
},
usu_password: {
  required: true
},
usu_email: {
  required: true
},
usu_nombre1: {
  required: true
},
usu_apellido1: {
  required: true
},
usu_fecha_nac: {
  required: true
},
usu_cedula: {
  required: true
},
usu_telefono1: {
  required: true
},
rol_id: {
  required: true
},
dependencia_id: {
  required: true
},
  },

  highlight: function(element) {
$(element).closest('.grupo').addClass('has-error');
        if($(".tab-content").find("div.tab-pane.active:has(div.has-error)").length == 0)
        {
            $(".tab-content").find("div.tab-pane:hidden:has(div.has-error)").each(function(index, tab)
            {
                var id = $(tab).attr("id");

                $('a[href="#' + id + '"]').tab('show');
            });
        }
  },
  unhighlight: function(element) {
$(element).closest('.grupo').removeClass('has-error');
  }
 });

}); // end document.ready

</script>

Answer 1

You can also directly use jQuery.

$('#myModal').is(':visible');

Answer 2

$("element").data('bs.modal').isShown

won't work if the modal hasn't been shown before. You will need to add an extra condition:

$("element").data('bs.modal')

so the answer taking into account first appearance:

if ($("element").data('bs.modal') && $("element").data('bs.modal').isShown){
... 
}

Answer 3

On bootstrap-modal.js v2.2.0:

( $('element').data('modal') || {}).isShown

Answer 4

You can use

$('#myModal').hasClass('in');

Bootstrap adds the in class when the modal is open and removes it when closed

Answer 5

Check if a modal is open

$('.modal:visible').length && $('body').hasClass('modal-open')

To attach an event listener

$(document).on('show.bs.modal', '.modal', function () {
    // run your validation... ( or shown.bs.modal )
});

Answer 6

To avoid the race condition @GregPettit mentions, one can use:

($("element").data('bs.modal') || {})._isShown    // Bootstrap 4
($("element").data('bs.modal') || {}).isShown     // Bootstrap <= 3

as discussed in Twitter Bootstrap Modal - IsShown.

When the modal is not yet opened, .data('bs.modal') returns undefined, hence the || {} - which will make isShown the (falsy) value undefined. If you're into strictness one could do ($("element").data('bs.modal') || {isShown: false}).isShown