Random alpha-numeric string in JavaScript? [duplic

Question

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• Generate random string/characters in JavaScript 59 answers

What's the shortest way (within reason) to generate a random alpha-numeric (uppercase, lowercase, and numbers) string in JavaScript to use as a probably-unique identifier?

Answer 1

One-liner with lodash, for random 20 characters (alphanumeric lowercase):

_.times(20, () => _.random(35).toString(36)).join('');

Answer 2

I think the following is the simplest solution which allows for a given length:

Array(myLength).fill(0).map(x => Math.random().toString(36).charAt(2)).join('')

It depends on the arrow function syntax.

Answer 3

Random Key Generator

keyLength argument is the character length you want for the key

function keyGen(keyLength) {
    var i, key = "", characters = "abcdefghijklmnopqrstuvwxyzABCDEFGHIJKLMNOPQRSTUVWXYZ0123456789";

    var charactersLength = characters.length;

    for (i = 0; i < keyLength; i++) {
        key += characters.substr(Math.floor((Math.random() * charactersLength) + 1), 1);
    }

    return key;
}


keyGen(12)
"QEt9mYBiTpYD"

Answer 4

Use md5 library: https://github.com/blueimp/JavaScript-MD5

The shortest way:

md5(Math.random())

If you want to limit the size to 5:

md5(Math.random()).substr(0, 5)

Answer 5

Random character:

String.fromCharCode(i); //where is an int

Random int:

Math.floor(Math.random()*100);

Put it all together:

function randomNum(hi){
    return Math.floor(Math.random()*hi);
} 
function randomChar(){
    return String.fromCharCode(randomNum(100));
}
function randomString(length){
   var str = "";
   for(var i = 0; i < length; ++i){
        str += randomChar();
   }
   return str;
}
var RandomString = randomString(32); //32 length string

Fiddle: http://jsfiddle.net/maniator/QZ9J2/

Answer 6

If you only want to allow specific characters, you could also do it like this:

function randomString(length, chars) {
    var result = '';
    for (var i = length; i > 0; --i) result += chars[Math.floor(Math.random() * chars.length)];
    return result;
}
var rString = randomString(32, '0123456789abcdefghijklmnopqrstuvwxyzABCDEFGHIJKLMNOPQRSTUVWXYZ');

Here's a jsfiddle to demonstrate: http://jsfiddle.net/wSQBx/

Another way to do it could be to use a special string that tells the function what types of characters to use. You could do that like this:

function randomString(length, chars) {
    var mask = '';
    if (chars.indexOf('a') > -1) mask += 'abcdefghijklmnopqrstuvwxyz';
    if (chars.indexOf('A') > -1) mask += 'ABCDEFGHIJKLMNOPQRSTUVWXYZ';
    if (chars.indexOf('#') > -1) mask += '0123456789';
    if (chars.indexOf('!') > -1) mask += '~`!@#$%^&*()_+-={}[]:";\'<>?,./|\\';
    var result = '';
    for (var i = length; i > 0; --i) result += mask[Math.floor(Math.random() * mask.length)];
    return result;
}

console.log(randomString(16, 'aA'));
console.log(randomString(32, '#aA'));
console.log(randomString(64, '#A!'));

Fiddle: http://jsfiddle.net/wSQBx/2/

Alternatively, to use the base36 method as described below you could do something like this:

function randomString(length) {
    return Math.round((Math.pow(36, length + 1) - Math.random() * Math.pow(36, length))).toString(36).slice(1);
}