How to define custom exception class in Java, the

2019-01-02 19:18发布

I'm trying to define my own exception class the easiest way, and this is what I'm getting:

public class MyException extends Exception {}

public class Foo {
  public bar() throws MyException {
    throw new MyException("try again please");
  }
}

This is what Java compiler says:

cannot find symbol: constructor MyException(java.lang.String)

I had a feeling that this constructor has to be inherited from java.lang.Exception, isn't it?

7条回答
皆成旧梦
2楼-- · 2019-01-02 20:10

No, you don't "inherit" non-default constructors, you need to define the one taking a String in your class. Typically you use super(message) in your constructor to invoke your parent constructor. For example, like this:

public class MyException extends Exception {
    public MyException(String message) {
        super(message);
    }
}
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