Generating a random password in php

Question

I am trying to generate a random password in php.

However I am getting all 'a's and the return type is of type array and I would like it to be a string. Any ideas on how to correct the code?

Thanks.

function randomPassword() {
    $alphabet = "abcdefghijklmnopqrstuwxyzABCDEFGHIJKLMNOPQRSTUWXYZ0123456789";
    for ($i = 0; $i < 8; $i++) {
        $n = rand(0, count($alphabet)-1);
        $pass[$i] = $alphabet[$n];
    }
    return $pass;
}

Answer 1

Tiny code with 2 line.

demo: http://codepad.org/5rHMHwnH

function rand_string( $length ) {

    $chars = "abcdefghijklmnopqrstuvwxyzABCDEFGHIJKLMNOPQRSTUVWXYZ0123456789";
    return substr(str_shuffle($chars),0,$length);

}

echo rand_string(8);

with rand_string you can define how much character will be create.

Answer 2

I created a more comprehensive and secure password script. This will create a combination of two uppercase, two lowercase, two numbers and two special characters. Total 8 characters.

$char = [range('A','Z'),range('a','z'),range(0,9),['*','%','$','#','@','!','+','?','.']];
$pw = '';
for($a = 0; $a < count($char); $a++)
{
    $randomkeys = array_rand($char[$a], 2);
    $pw .= $char[$a][$randomkeys[0]].$char[$a][$randomkeys[1]];
}
$userPassword = str_shuffle($pw);

Answer 3

<?php
    // We can generate without large code..
    $length = 8;
    $chars = array_merge(range(0,9), range('a','z'),range('A','Z'),['!','@','#','$','%','&','*','?']);
    //$chars = array_merge(range(0,1), range('A','Z'));
    shuffle($chars);
    $code = implode(array_slice($chars, 0, $length));
    $arr = array($code);
    $password = implode("",$arr);
    echo $password;

Answer 4

I know you are trying to generate your password in a specific way, but you might want to look at this method as well...

$bytes = openssl_random_pseudo_bytes(2);

$pwd = bin2hex($bytes);

It's taken from the php.net site and it creates a string which is twice the length of the number you put in the openssl_random_pseudo_bytes function. So the above would create a password 4 characters long.

In short...

$pwd = bin2hex(openssl_random_pseudo_bytes(4));

Would create a password 8 characters long.

Note however that the password only contains numbers 0-9 and small cap letters a-f!

Answer 5

In one line:

substr(str_shuffle('abcdefghijklmnopqrstuvwxyzABCDEFGHIJKLMNOPQRSTUVWXYZ0123456789') , 0 , 10 )

Answer 6

Try This with Capital Letters, Small Letters, Numeric(s) and Special Characters

function generatePassword($_len) {

    $_alphaSmall = 'abcdefghijklmnopqrstuvwxyz';            // small letters
    $_alphaCaps  = strtoupper($_alphaSmall);                // CAPITAL LETTERS
    $_numerics   = '1234567890';                            // numerics
    $_specialChars = '`~!@#$%^&*()-_=+]}[{;:,<.>/?\'"\|';   // Special Characters

    $_container = $_alphaSmall.$_alphaCaps.$_numerics.$_specialChars;   // Contains all characters
    $password = '';         // will contain the desired pass

    for($i = 0; $i < $_len; $i++) {                                 // Loop till the length mentioned
        $_rand = rand(0, strlen($_container) - 1);                  // Get Randomized Length
        $password .= substr($_container, $_rand, 1);                // returns part of the string [ high tensile strength ;) ] 
    }

    return $password;       // Returns the generated Pass
}

Let's Say we need 10 Digit Pass

echo generatePassword(10);  

Example Output(s) :

,IZCQ_IV\7

@wlqsfhT(d

1!8+1\4@uD