How to get everything after last slash in a URL?

Question

How can I extract whatever follows the last slash in a URL in Python? For example, these URLs should return the following:

URL: http://www.test.com/TEST1
returns: TEST1

URL: http://www.test.com/page/TEST2
returns: TEST2

URL: http://www.test.com/page/page/12345
returns: 12345

I've tried urlparse, but that gives me the full path filename, such as page/page/12345.

Answer 1

Here's a more general, regex way of doing this:

    re.sub(r'^.+/([^/]+)$', r'\1', url)

Answer 2

os.path.basename(os.path.normpath('/folderA/folderB/folderC/folderD/'))

folderD

Answer 3

One more (idio(ma)tic) way:

URL.split("/")[-1]

Answer 4

rsplit should be up to the task:

In [1]: 'http://www.test.com/page/TEST2'.rsplit('/', 1)[1]
Out[1]: 'TEST2'

Answer 5

Split the url and pop the last element url.split('/').pop()

Answer 6

extracted_url = url[url.rfind("/")+1:];