java.lang.IllegalArgumentException: contains a pat

Question

I have a filename in my code as :

String NAME_OF_FILE="//sdcard//imageq.png";
FileInputStream fis =this.openFileInput(NAME_OF_FILE); // 2nd line

I get an error on 2nd line :

05-11 16:49:06.355: ERROR/AndroidRuntime(4570): Caused by: java.lang.IllegalArgumentException: File //sdcard//imageq.png contains a path separator

I tried this format also:

String NAME_OF_FILE="/sdcard/imageq.png";

Answer 1

I solved this type of error by making a directory in the onCreate event, then accessing the directory by creating a new file object in a method that needs to do something such as save or retrieve a file in that directory, hope this helps!

 public class MyClass {    

 private String state;
 public File myFilename;

 @Override
 protected void onCreate(Bundle savedInstanceState) {//create your directory the user will be able to find
    super.onCreate(savedInstanceState);
    if (Environment.MEDIA_MOUNTED.equals(state)) {
        myFilename = new File(Environment.getExternalStorageDirectory().toString() + "/My Directory");
        if (!myFilename.exists()) {
            myFilename.mkdirs();
        }
    }
 }

 public void myMethod {

 File fileTo = new File(myFilename.toString() + "/myPic.png");  
 // use fileTo object to save your file in your new directory that was created in the onCreate method
 }
}

Answer 2

The solution is:

FileInputStream fis = new FileInputStream (new File(NAME_OF_FILE));  // 2nd line

The openFileInput method doesn't accept path separators.

Don't forget to

fis.close();

at the end.

Answer 3

I got the above error message while trying to access a file from Internal Storage using openFileInput("/Dir/data.txt") method with subdirectory Dir.

You cannot access sub-directories using the above method.

Try something like:

FileInputStream fIS = new FileInputStream (new File("/Dir/data.txt"));

Answer 4

openFileInput() doesn't accept paths, only a file name if you want to access a path, use File file = new File(path) and corresponding FileInputStream

Answer 5

File file = context.getFilesDir(); 
file.mkdir();
String[] array = filePath.split("/"); 
for(int t = 0; t < array.length - 1; t++) {
    file = new File(file, array[t]); 
    file.mkdir();
}
File f = new File(file,array[array.length- 1]); 
RandomAccessFileOutputStream rvalue = 
    new RandomAccessFileOutputStream(f, append);

Answer 6

You cannot use path with directory separators directly, but you will have to make a file object for every directory.

NOTE: This code makes directories, yours may not need that...

File file= context.getFilesDir();
file.mkdir();

String[] array=filePath.split("/");
for(int t=0; t< array.length -1 ;t++)
{
    file=new File(file,array[t]);
    file.mkdir();
}

File f=new File(file,array[array.length-1]);

RandomAccessFileOutputStream rvalue = new RandomAccessFileOutputStream(f,append);