Is it possible only to declare a variable without

2019-01-20 23:09发布

Is it possible to declare a variable in Python, like so?:

var

so that it initialized to None? It seems like Python allows this, but as soon as you access it, it crashes. Is this possible? If not, why?

EDIT: I want to do this for cases like this:

value

for index in sequence:

   if value == None and conditionMet:
       value = index
       break

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13条回答
叼着烟拽天下
2楼-- · 2019-01-20 23:24

You can trick an interpreter with this ugly oneliner if None: var = None It do nothing else but adding a variable var to local variable dictionary, not initializing it. Interpreter will throw the UnboundLocalError exception if you try to use this variable in a function afterwards. This would works for very ancient python versions too. Not simple, nor beautiful, but don't expect much from python.

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forever°为你锁心
3楼-- · 2019-01-20 23:27

Why not just do this:

var = None

Python is dynamic, so you don't need to declare things; they exist automatically in the first scope where they're assigned. So, all you need is a regular old assignment statement as above.

This is nice, because you'll never end up with an uninitialized variable. But be careful -- this doesn't mean that you won't end up with incorrectly initialized variables. If you init something to None, make sure that's what you really want, and assign something more meaningful if you can.

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The star\"
4楼-- · 2019-01-20 23:27

I usually initialize the variable to something that denotes the type like

var = ""

or

var = 0

If it is going to be an object then don't initialize it until you instantiate it:

var = Var()
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时光不老,我们不散
5楼-- · 2019-01-20 23:30
var_str = str()
var_int = int()
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beautiful°
6楼-- · 2019-01-20 23:32

First of all, my response to the question you've originally asked

Q: How do I discover if a variable is defined at a point in my code?

A: Read up in the source file until you see a line where that variable is defined.

But further, you've given a code example that there are various permutations of that are quite pythonic. You're after a way to scan a sequence for elements that match a condition, so here are some solutions:

def findFirstMatch(sequence):
    for value in sequence:
        if matchCondition(value):
            return value

    raise LookupError("Could not find match in sequence")

Clearly in this example you could replace the raise with a return None depending on what you wanted to achieve.

If you wanted everything that matched the condition you could do this:

def findAllMatches(sequence):
    matches = []
    for value in sequence:
        if matchCondition(value):
            matches.append(value)

    return matches

There is another way of doing this with yield that I won't bother showing you, because it's quite complicated in the way that it works.

Further, there is a one line way of achieving this:

all_matches = [value for value in sequence if matchCondition(value)]
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一纸荒年 Trace。
7楼-- · 2019-01-20 23:34

I'd heartily recommend that you read Other languages have "variables" (I added it as a related link) – in two minutes you'll know that Python has "names", not "variables".

val = None
# ...
if val is None:
   val = any_object
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