How do I read a string entered by the user in C?

Question

I want to read the name entered by my user using C programmes.

For this I wrote:

char name[20];

printf("Enter name: ");
gets(name);

But using gets is not good, so what is a better way?

Answer 1

On BSD systems and Android you can also use fgetln:

#include <stdio.h>

char *
fgetln(FILE *stream, size_t *len);

Like so:

size_t line_len;
const char *line = fgetln(stdin, &line_len);

The line is not null terminated and contains \n (or whatever your platform is using) in the end. It becomes invalid after the next I/O operation on stream. You are allowed to modify the returned line buffer.

Answer 2

I think the best and safest way to read strings entered by the user is using getline()

Here's an example how to do this:

#include <stdio.h>
#include <stdlib.h>
int main(int argc, char *argv[])
{
    char *buffer = NULL;
    int read;
    unsigned int len;
    read = getline(&buffer, &len, stdin);
    if (-1 != read)
        puts(buffer);
    else
        printf("No line read...\n");

    printf("Size read: %d\n Len: %d\n", read, len);
    free(buffer);
    return 0;
}

Answer 3

On a POSIX system, you probably should use getline if it's available.

You also can use Chuck Falconer's public domain ggets function which provides syntax closer to gets but without the problems. (Chuck Falconer's website is no longer available, although archive.org has a copy, and I've made my own page for ggets.)

Answer 4

You can use scanf function to read string

scanf("%[^\n]",name);

i don't know about other better options to receive string,

Answer 5

You should never use gets (or scanf with an unbounded string size) since that opens you up to buffer overflows. Use the fgets with a stdin handle since it allows you to limit the data that will be placed in your buffer.

Here's a little snippet I use for line input from the user:

#include <stdio.h>
#include <string.h>

#define OK       0
#define NO_INPUT 1
#define TOO_LONG 2
static int getLine (char *prmpt, char *buff, size_t sz) {
    int ch, extra;

    // Get line with buffer overrun protection.
    if (prmpt != NULL) {
        printf ("%s", prmpt);
        fflush (stdout);
    }
    if (fgets (buff, sz, stdin) == NULL)
        return NO_INPUT;

    // If it was too long, there'll be no newline. In that case, we flush
    // to end of line so that excess doesn't affect the next call.
    if (buff[strlen(buff)-1] != '\n') {
        extra = 0;
        while (((ch = getchar()) != '\n') && (ch != EOF))
            extra = 1;
        return (extra == 1) ? TOO_LONG : OK;
    }

    // Otherwise remove newline and give string back to caller.
    buff[strlen(buff)-1] = '\0';
    return OK;
}

This allows me to set the maximum size, will detect if too much data is entered on the line, and will flush the rest of the line as well so it doesn't affect the next input operation.

You can test it with something like:

// Test program for getLine().

int main (void) {
    int rc;
    char buff[10];

    rc = getLine ("Enter string> ", buff, sizeof(buff));
    if (rc == NO_INPUT) {
        // Extra NL since my system doesn't output that on EOF.
        printf ("\nNo input\n");
        return 1;
    }

    if (rc == TOO_LONG) {
        printf ("Input too long [%s]\n", buff);
        return 1;
    }

    printf ("OK [%s]\n", buff);

    return 0;
}

Answer 6

I found an easy and nice solution:

char*string_acquire(char*s,int size,FILE*stream){
    int i;
    fgets(s,size,stream);
    i=strlen(s)-1;
    if(s[i]!='\n') while(getchar()!='\n');
    if(s[i]=='\n') s[i]='\0';
    return s;
}

it's based on fgets but free from '\n' and stdin extra characters (to replace fflush(stdin) that doesn't works on all OS, useful if you have to acquire strings after this).