Make absolute positioned div expand parent div hei

2019-01-02 18:24发布

As you can see in the CSS below, I want child2 to position itself before child1. This is because the site I'm currently developing should also work on mobile devices, on which the child2 should be at the bottom, as it contains the navigation which I want below the content on the mobile devices. - Why not 2 masterpages? This is the only 2 divs which are repositioned in the entire HTML, so 2 masterpages for this minor change is an overkill.

HTML:

<div id="parent">
    <div class="child1"></div>
    <div class="child2"></div>
</div>

CSS:

parent { position: relative; width: 100%; }
child1 { width: auto; margin-left: 160px; }
child2 { width: 145px; position: absolute; top: 0px; bottom: 0px; }

child2 has dynamic height, as different subsites could have more or less navigation items.

I know that absolute positioned elements are removed from the flow, thus ignored by other elements.
I tried setting overflow:hidden; on the parent div, but that didn't help, neither does the clearfix.

My last resort will be javascript to reposition the two divs accordingly, but for now I'll try and see if there exist a non-javascript way of doing this.

13条回答
ら面具成の殇う
2楼-- · 2019-01-02 18:56

Also consider next approach:

CSS:

.parent {
  height: 100%;
}
.parent:after {
  content: '';
  display: block;
}

Also since you are trying to reposition divs consider css grid

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情到深处是孤独
3楼-- · 2019-01-02 18:57

"You either use fixed heights or you need to involve JS."

Here is the JS example:

---------- jQuery JS example--------------------

    function findEnvelopSizeOfAbsolutelyPositionedChildren(containerSelector){
        var maxX = $(containerSelector).width(), maxY = $(containerSelector).height();

        $(containerSelector).children().each(function (i){
            if (maxX < parseInt($(this).css('left')) + $(this).width()){
                maxX = parseInt($(this).css('left')) + $(this).width();
            }
            if (maxY < parseInt($(this).css('top')) + $(this).height()){
                maxY = parseInt($(this).css('top')) + $(this).height();
            }
        });
        return {
            'width': maxX,
            'height': maxY
        }
    }

    var specBodySize = findEnvelopSizeOfAbsolutelyPositionedSubDivs("#SpecBody");
    $("#SpecBody").width(specBodySize.width);
    $("#SpecBody").height(specBodySize.height);
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高级女魔头
4楼-- · 2019-01-02 18:58

You answered the question by yourself: "I know that absolute positioned elements are removed from the flow, thus ignored by other elements." So you can't set the parents height according to an absolutely positioned element.

You either use fixed heights or you need to involve JS.

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旧时光的记忆
5楼-- · 2019-01-02 18:59

Absolute views position themselves against the nearest ancestor that isn't statically positioned (position: static), therefore if you want an absolute view positioned against a given parent, set the parent position to relative and the child to position to absolute

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路过你的时光
6楼-- · 2019-01-02 18:59

Try this, it was worked for me

.child {
    width: 100%;
    position: absolute;
    top: 0px;
    bottom: 0px;
    z-index: 1;
}

It will set child height to parent height

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妖精总统
7楼-- · 2019-01-02 19:00

Although stretching to elements with position: absolute is not possible, there are often solutions where you can avoid the absolute positioning while obtaining the same effect. Look at this fiddle that solves the problem in your particular case http://jsfiddle.net/gS9q7/

The trick is to reverse element order by floating both elements, the first to the right, the second to the left, so the second appears first.

.child1 {
    width: calc(100% - 160px);
    float: right;
}
.child2 {
    width: 145px;
    float: left;
}

Finally, add a clearfix to the parent and you're done (see the fiddle for the complete solution).

Generally, as long as the element with absolute position is positioned at the top of the parent element, chances are good that you find a workaround by floating the element.

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