cannot subscript a value of type 'inout' [

2019-01-20 18:21发布

How can if i try to add three menus in the dictionary i wont let me and throws an error when i try to force unwrap the 3rd item in the menu. However if i force unwrap two of them, i can get them sum of two

var menu = ["fish": 10.99, "chips": 5.99, "kebab": 6.99]
var totalCost = menu["fish"]! + menu["chips"]! + menu["kebab"]!
print("The total cost of the three items is \(totalCost)")

But when i tried it this way it worked

var menu = ["fish": 10.99, "chips": 5.99, "kebab": 6.99]
var totalCost = menu["fish"]! + menu["chips"]! 
var thisCost = totalCost + menu["kebab"]!
print("The total cost of the three items is \(thisCost)"

I am using swift 3. Could it be that can no longer be supported in swift 3?

1条回答
戒情不戒烟
2楼-- · 2019-01-20 18:41

You can alway iterate through and add to total, much simpler that a line of long addition.

var totalCost: Double = 0
for each in menu {
    totalCost += each.value
}
print(totalCost)
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