Converting integer to binary in python

Question

In order to convert an integer to a binary, i have used this code :

>>> bin(6)  
'0b110'

and when to erase the '0b', i use this :

>>> bin(6)[2:]  
'110'

What can i do if i want to show 6 as 00000110 instead of 110?

Answer 1

eumiro's answer is better, however I'm just posting this for variety:

>>> "%08d" % int(bin(6)[2:])
00000110

Answer 2

>>> '{0:08b}'.format(6)
'00000110'

Just to explain the parts of the formatting string:

• {} places a variable into a string
• 0 takes the variable at argument position 0
• : adds formatting options for this variable (otherwise it would represent decimal 6)
• 08 formats the number to eight digits zero-padded on the left
• b converts the number to its binary representation

Answer 3

Going Old School always works

def intoBinary(number):
binarynumber=""
if (number!=0):
    while (number>=1):
        if (number %2==0):
            binarynumber=binarynumber+"0"
            number=number/2
        else:
            binarynumber=binarynumber+"1"
            number=(number-1)/2

else:
    binarynumber="0"

return "".join(reversed(binarynumber))

Answer 4

A bit twiddling method...

>>> bin8 = lambda x : ''.join(reversed( [str((x >> i) & 1) for i in range(8)] ) )
>>> bin8(6)
'00000110'
>>> bin8(-3)
'11111101'

Answer 5

Just use the format function

format(6, "08b")

The general form is

format(<the_integer>, "<0><width_of_string><format_specifier>")

Answer 6

Just another idea:

>>> bin(6)[2:].zfill(8)
'00000110'

Shorter way via string interpolation (Python 3.6+):

>>> f'{6:08b}'
'00000110'