What's the difference between __PRETTY_FUNCTIO

2019-01-02 16:38发布

What's the difference between __PRETTY_FUNCTION__, __FUNCTION__, __func__, and where are they documented? How do I decide which one to use?

5条回答
谁念西风独自凉
2楼-- · 2019-01-02 17:07

__PRETTY_FUNCTION__ handles C++ features: classes, namespaces, templates and overload

#include <iostream>

namespace N {
    class C {
        public:
            template <class T>
            static void f(int i) {
                std::cout << __func__ << std::endl
                          << __FUNCTION__ << std::endl
                          << __PRETTY_FUNCTION__ << std::endl;
            }
            template <class T>
            static void f(double f) {
                std::cout << __PRETTY_FUNCTION__ << std::endl;
            }
    };
}

int main() {
    N::C::f<char>(1);
    N::C::f<void>(1.0);
}

Output GCC 7.2 g++ -std=gnu++98:

f
f
static void N::C::f(int) [with T = char]
static void N::C::f(double) [with T = void]
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初与友歌
3楼-- · 2019-01-02 17:09

For those, who wonder how it goes in VS.

MSVC 2015 Update 1, cl.exe version 19.00.24215.1:

#include <iostream>

template<typename X, typename Y>
struct A
{
  template<typename Z>
  static void f()
  {
    std::cout << "from A::f():" << std::endl
      << __FUNCTION__ << std::endl
      << __func__ << std::endl
      << __FUNCSIG__ << std::endl;
  }
};

void main()
{
  std::cout << "from main():" << std::endl
    << __FUNCTION__ << std::endl
    << __func__ << std::endl
    << __FUNCSIG__ << std::endl << std::endl;

  A<int, float>::f<bool>();
}

output:

from main():
main
main
int __cdecl main(void)

from A::f():
A<int,float>::f
f
void __cdecl A<int,float>::f<bool>(void)

Using of __PRETTY_FUNCTION__ triggers undeclared identifier error, as expected.

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一个人的天荒地老
4楼-- · 2019-01-02 17:27

__func__ is documented in the C++0x standard at section 8.4.1. In this case it's a predefined function local variable of the form:

static const char __func__[] = "function-name ";

where "function name" is implementation specfic. This means that whenever you declare a function, the compiler will add this variable implicitly to your function. The same is true of __FUNCTION__ and __PRETTY_FUNCTION__. Despite their uppercasing, they aren't macros. Although __func__ is an addition to C++0x

g++ -std=c++98 ....

will still compile code using __func__.

__PRETTY_FUNCTION__ and __FUNCTION__ are documented here http://gcc.gnu.org/onlinedocs/gcc-4.5.1/gcc/Function-Names.html#Function-Names. __FUNCTION__ is just another name for __func__. __PRETTY_FUNCTION__ is the same as __func__ in C but in C++ it contains the type signature as well.

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孤独总比滥情好
5楼-- · 2019-01-02 17:31

__func__ is an implicitly declared identifier that expands to a character array variable containing the function name when it is used inside of a function. It was added to C in C99. From C99 §6.4.2.2/1:

The identifier __func__ is implicitly declared by the translator as if, immediately following the opening brace of each function definition, the declaration

static const char __func__[] = "function-name";

appeared, where function-name is the name of the lexically-enclosing function. This name is the unadorned name of the function.

Note that it is not a macro and it has no special meaning during preprocessing.

__func__ was added to C++ in C++11, where it is specified as containing "an implementation-defined string" (C++11 §8.4.1[dcl.fct.def.general]/8), which is not quite as useful as the specification in C. (The original proposal to add __func__ to C++ was N1642).

__FUNCTION__ is a pre-standard extension that some C compilers support (including gcc and Visual C++); in general, you should use __func__ where it is supported and only use __FUNCTION__ if you are using a compiler that does not support it (for example, Visual C++, which does not support C99 and does not yet support all of C++0x, does not provide __func__).

__PRETTY_FUNCTION__ is a gcc extension that is mostly the same as __FUNCTION__, except that for C++ functions it contains the "pretty" name of the function including the signature of the function. Visual C++ has a similar (but not quite identical) extension, __FUNCSIG__.

For the nonstandard macros, you will want to consult your compiler's documentation. The Visual C++ extensions are included in the MSDN documentation of the C++ compiler's "Predefined Macros". The gcc documentation extensions are described in the gcc documentation page "Function Names as Strings."

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其实,你不懂
6楼-- · 2019-01-02 17:31

Despite this doesn't fully answer the original question, it's what most of people who google this might wanted to see

For GCC:

petanb@debian:~$ cat test.cpp 
#include <iostream>

int main(int argc, char **argv)
{
    std::cout << __func__ << std::endl
              << __FUNCTION__ << std::endl
              << __PRETTY_FUNCTION__ << std::endl;
}
petanb@debian:~$ g++ test.cpp 
petanb@debian:~$ 
petanb@debian:~$ ./a.out 
main
main
int main(int, char**)
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