How can I handle the warning of file_get_contents&

Question

I wrote a PHP code like this

$site="http://www.google.com";
$content = file_get_content($site);
echo $content;

But when I remove "http://" from $site I get the following warning:

Warning: file_get_contents(www.google.com) [function.file-get-contents]: failed to open stream:

I tried try and catch but it didn't work.

Answer 1

Here's how I did it... No need for try-catch block... The best solution is always the simplest... Enjoy!

$content = @file_get_contents("http://www.google.com");
if (strpos($http_response_header[0], "200")) { 
   echo "SUCCESS";
} else { 
   echo "FAILED";
} 

Answer 2

You can also set your error handler as an anonymous function that calls an Exception and use a try / catch on that exception.

set_error_handler(
    function ($severity, $message, $file, $line) {
        throw new ErrorException($message, $severity, $severity, $file, $line);
    }
);

try {
    file_get_contents('www.google.com');
}
catch (Exception $e) {
    echo $e->getMessage();
}

restore_error_handler();

Seems like a lot of code to catch one little error, but if you're using exceptions throughout your app, you would only need to do this once, way at the top (in an included config file, for instance), and it will convert all your errors to Exceptions throughout.

Answer 3

You should use file_exists() function before to use file_get_contents(). With this way you'll avoid the php warning.

$file = "path/to/file";

if(file_exists($file)){
  $content = file_get_contents($file);
}

Answer 4

You should also set the

allow_url_use = On 

in your php.ini to stop receiving warnings.