when to carefully use free() to free up malloc() u

2019-01-19 06:50发布

I read from many question here in SO and some other articles regarding free() function in c that frees the memory of unused variables. In my case, I have the following code block.

char *injectStrAt(char *str, char *strToIn, int pos)
{
    char *strC = malloc(strlen(str) + strlen(strToIn) + 1);
    strncpy(strC, str, pos);
    strC[pos] = '\0';
    strcat(strC, strToIn);
    strcat(strC, str + pos);
    return strC;
}

The above function I use to inject a string block in to an array. I am using malloc to create a new char*. In the above case do I need to do free(strC) ? advice pls.

标签: c malloc free
3条回答
beautiful°
2楼-- · 2019-01-19 07:10

No you shouldn't free strC inside this function because it is the return value of this function. If you do so the statement:

return strC;

will return some unexpected or garbage value.

char* stringA = injectStrAt(str, strToIn, pos);
printf("StringA: %s"); // unexpected value.

So when should you free up the memory? Well, you should do it after the value of strC is returned from the function injectStrAt() to stringA, in this particular case. Although generally memory is freed when the string or the variable to which the memory was allocated is no longer required.

char* stringA = injectStrAt(str, strToIn, pos);
/... use the string

free(stringA);
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我想做一个坏孩纸
3楼-- · 2019-01-19 07:19

strC is the return value of this function, so you don't call free(strC) inside the function itself. You need to free it outside the function, the time when this string is not used anymore.

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太酷不给撩
4楼-- · 2019-01-19 07:28

Since your function is returning strC, one presumes it must remain valid after the return of this function, thus this function must not free() that buffer. Once it's freed, the buffer is no longer valid so must not be used.

Your caller is responsible for freeing it in this case.

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