Environment variable substitution in sed

2019-01-02 15:09发布

If I run these commands from a script:

#my.sh
PWD=bla
sed 's/xxx/'$PWD'/'
...
$ ./my.sh
xxx
bla

it is fine.

But, if I run:

#my.sh
sed 's/xxx/'$PWD'/'
...
$ ./my.sh
$ sed: -e expression #1, char 8: Unknown option to `s' 

I read in tutorials that to substitute environment variables from shell you need to stop, and 'out quote' the $varname part so that it is not substituted directly, which is what I did, and which works only if the variable is defined immediately before.

How can I get sed to recognize a $var as an environment variable as it is defined in the shell?

10条回答
旧时光的记忆
2楼-- · 2019-01-02 15:56

Your two examples look identical, which makes problems hard to diagnose. Potential problems:

  1. You may need double quotes, as in sed 's/xxx/'"$PWD"'/'

  2. $PWD may contain a slash, in which case you need to find a character not contained in $PWD to use as a delimiter.

To nail both issues at once, perhaps

sed 's@xxx@'"$PWD"'@'
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大哥的爱人
3楼-- · 2019-01-02 16:00

Another easy alternative:

Since $PWD will usually contain a slash /, use | instead of / for the sed statement:

sed -e "s|xxx|$PWD|"
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与风俱净
4楼-- · 2019-01-02 16:02

In addition to Norman Ramsey's answer, I'd like to add that you can double-quote the entire string (which may make the statement more readable and less error prone).

So if you want to search for 'foo' and replace it with the content of $BAR, you can enclose the sed command in double-quotes.

sed 's/foo/$BAR/g'
sed "s/foo/$BAR/g"

In the first, $BAR will not expand correctly while in the second $BAR will expand correctly.

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忆尘夕之涩
5楼-- · 2019-01-02 16:05

With your question edit, I see your problem. Let's say the current directory is /home/yourname ... in this case, your command below:

sed 's/xxx/'$PWD'/'

will be expanded to

sed `s/xxx//home/yourname//

which is not valid. You need to put a \ character in front of each / in your $PWD if you want to do this.

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