PostgreSQL GROUP BY different from MySQL?

2019-01-02 14:53发布

I've been migrating some of my MySQL queries to PostgreSQL to use Heroku. Most of my queries work fine, but I keep having a similar recurring error when I use group by:

ERROR: column "XYZ" must appear in the GROUP BY clause or be used in an aggregate function

Could someone tell me what I'm doing wrong?


MySQL which works 100%:

SELECT `availables`.*
FROM `availables`
INNER JOIN `rooms` ON `rooms`.id = `availables`.room_id
WHERE (rooms.hotel_id = 5056 AND availables.bookdate BETWEEN '2009-11-22' AND '2009-11-24')
GROUP BY availables.bookdate
ORDER BY availables.updated_at


PostgreSQL error:

ActiveRecord::StatementInvalid: PGError: ERROR: column "availables.id" must appear in the GROUP BY clause or be used in an aggregate function:
SELECT "availables".* FROM "availables" INNER JOIN "rooms" ON "rooms".id = "availables".room_id WHERE (rooms.hotel_id = 5056 AND availables.bookdate BETWEEN E'2009-10-21' AND E'2009-10-23') GROUP BY availables.bookdate ORDER BY availables.updated_at


Ruby code generating the SQL:

expiration = Available.find(:all,
    :joins => [ :room ],
    :conditions => [ "rooms.hotel_id = ? AND availables.bookdate BETWEEN ? AND ?", hostel_id, date.to_s, (date+days-1).to_s ],
    :group => 'availables.bookdate',
    :order => 'availables.updated_at')  


Expected Output (from working MySQL query):

+-----+-------+-------+------------+---------+---------------+---------------+
| id  | price | spots | bookdate   | room_id | created_at    | updated_at    |
+-----+-------+-------+------------+---------+---------------+---------------+
| 414 | 38.0  | 1     | 2009-11-22 | 1762    | 2009-11-20... | 2009-11-20... |
| 415 | 38.0  | 1     | 2009-11-23 | 1762    | 2009-11-20... | 2009-11-20... |
| 416 | 38.0  | 2     | 2009-11-24 | 1762    | 2009-11-20... | 2009-11-20... |
+-----+-------+-------+------------+---------+---------------+---------------+
3 rows in set

9条回答
低头抚发
2楼-- · 2019-01-02 15:35

PostgreSQL is more SQL compliant than MySQL. All fields - except computed field with aggregation function - in the output must be present in the GROUP BY clause.

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荒废的爱情
3楼-- · 2019-01-02 15:38

If I remember correctly, in PostgreSQL you have to add every column you fetch from the table where the GROUP BY clause applies to the GROUP BY clause.

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大哥的爱人
4楼-- · 2019-01-02 15:39

Correct, the solution to fixing this is to use :select and to select each field that you wish to decorate the resulting object with and group by them.

Nasty - but it is how group by should work as opposed to how MySQL works with it by guessing what you mean if you don't stick fields in your group by.

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余欢
5楼-- · 2019-01-02 15:41

Not the prettiest solution, but changing the group parameter to output every column in model works in PostgreSQL:

expiration = Available.find(:all,
:joins => [ :room ],
:conditions => [ "rooms.hotel_id = ? AND availables.bookdate BETWEEN ? AND ?", hostel_id, date.to_s, (date+days-1).to_s ],
:group => Available.column_names.collect{|col| "availables.#{col}"},
:order => 'availables.updated_at')
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深知你不懂我心
6楼-- · 2019-01-02 15:42

For others looking for a way to order by any field, including joined field, in postgresql, use a subquery:

SELECT * FROM(
SELECT DISTINCT ON(availables.bookdate) `availables`.* 
FROM `availables` INNER JOIN `rooms` ON `rooms`.id = `availables`.room_id 
WHERE (rooms.hotel_id = 5056 
AND availables.bookdate BETWEEN '2009-11-22' AND '2009-11-24')
) AS distinct_selected
ORDER BY availables.updated_at

or arel:

subquery = SomeRecord.select("distinct on(xx.id) xx.*, jointable.order_field")
      .where("").joins(")
result = SomeRecord.select("*").from("(#{subquery.to_sql}) AS distinct_selected").order(" xx.order_field ASC, jointable.order_field ASC")
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墨雨无痕
7楼-- · 2019-01-02 15:44

MySQL's totally non standards compliant GROUP BY can be emulated by Postgres' DISTINCT ON. Consider this:

MySQL:

SELECT a,b,c,d,e FROM table GROUP BY a

This delivers 1 row per value of a (which one, you don't really know). Well actually you can guess, because MySQL doesn't know about hash aggregates, so it will probably use a sort... but it will only sort on a, so the order of the rows could be random. Unless it uses a multicolumn index instead of sorting. Well, anyway, it's not specified by the query.

Postgres:

SELECT DISTINCT ON (a) a,b,c,d,e FROM table ORDER BY a,b,c

This delivers 1 row per value of a, this row will be the first one in the sort according to the ORDER BY specified by the query. Simple.

Note that here, it's not an aggregate I'm computing. So GROUP BY actually makes no sense. DISTINCT ON makes a lot more sense.

Rails is married to MySQL, so I'm not surprised that it generates SQL that doesn't work in Postgres.

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