How to force Selenium WebDriver to click on elemen

2019-01-02 14:55发布

I am using Selenium 2 Java API with FirefoxDriver. When I fill a form, checkboxes are added to the page depending the forms inputs.

I'd like to simulate a click on those checkboxes using Selenium. The element are visible and usable in a regular browser but, selenium asserts that the elements are not visible.

"Element is not currently visible and so may not be interacted with"

Can I force selenium to ignore the non-visible state of the elements? How can I force Selenium to interact with the non-visible element?

13条回答
浪荡孟婆
2楼-- · 2019-01-02 15:23

There is also another case when visible element will be recognized as not visible:

  • When the Element is CSS transformed
  • When Parent Element of the Element is CSS transformed

In order to check if element you wan't to interact with is CSS transformed, on CHROME do this:

  1. open inspector
  2. Find interesting element (or more likely its parent element, supposedly div element)
  3. Select 'Computed' tab
  4. if there is a parameter: webkit-transform: matrix( ... ) it means that the element is CSS transformed, and may not be recognized by selenium 2 as a visible element
查看更多
牵手、夕阳
3楼-- · 2019-01-02 15:24

Or you may use Selenium Action Class to simulate user interaction -- For example

    WebDriver = new FirefoxDriver();

    WebElement menu = driver.findElement(By.xpath("")); // the triger event element

    Actions build = new Actions(driver); // heare you state ActionBuider
    build.moveToElement(menu).build().perform(); // Here you perform hover mouse over the needed elemnt to triger the visibility of the hidden
    WebElement m2m= driver.findElement(By.xpath(""));//the previous non visible element
    m2m.click();
查看更多
明月照影归
4楼-- · 2019-01-02 15:27

I get into ElementNotVisibleException exception using selenium for functional tests on a django site with bootstrap glyphicons as links in templates as:

<a href="{% url 'item-add' %}"><span class="glyphicon glyphicon-plus text-danger"></span></a>

During my functional tests, the bootstrap style is not loaded, then trying to click on such links will raise ElementNotVisibleException. I manage to make them clickable just adding a space in the tag, like that:

<a href="{% url 'item-add' %}"><span class="glyphicon glyphicon-plus text-danger">&nbsp;</span></a>
查看更多
爱死公子算了
5楼-- · 2019-01-02 15:27

The accepted answer worked for me. Below is some code to find the parent element that's making Selenium think it's not visible.

function getStyles(element){
	
	computedStyle = window.getComputedStyle(element);

	if(computedStyle.opacity === 0
	|| computedStyle.display === "none"
	|| computedStyle.visibility === "hidden"
	|| (computedStyle.height < 0 && computedStyle.height < 0)
	|| element.type === "hidden") {
		console.log("Found an element that Selenium will consider to not be visible")
		console.log(element);
		console.log("opacity: " + computedStyle.opacity);
		console.log("display: " + computedStyle.display);
		console.log("visibility: " + computedStyle.visibility);
		console.log("height: " + computedStyle.height);
		console.log("width: " + computedStyle.width);
	}

	if(element.parentElement){
		getStyles(element.parentElement);
	}
}

getStyles(document.getElementById('REPLACE WITH THE ID OF THE ELEMENT YOU THINK IS VISIBLE BUT SELENIUM CAN NOT FIND'));

查看更多
闭嘴吧你
6楼-- · 2019-01-02 15:30

I just solve this error by waiting element display property

waitFor() { element.displayed }
查看更多
只若初见
7楼-- · 2019-01-02 15:33

Selenium determines an element is visible or not by the following criteria (use a DOM inspector to determine what css applies to your element, make sure you look at computed style):

  • visibility != hidden
  • display != none (is also checked against every parent element)
  • opacity != 0 (this is not checked for clicking an element)
  • height and width are both > 0
  • for an input, the attribute type != hidden

Your element is matching one of those criteria. If you do not have the ability to change the styling of the element, here is how you can forcefully do it with javascript (going to assume WebDriver since you said Selenium2 API):

((JavascriptExecutor)driver).executeScript("arguments[0].checked = true;", inputElement);

But that won't fire a javascript event, if you depend on the change event for that input you'll have to fire it too (many ways to do that, easiest to use whatever javascript library is loaded on that page).

The source for the visibility check -

https://github.com/SeleniumHQ/selenium/blob/master/javascript/atoms/dom.js#L577

The WebDriver spec that defines this -

https://dvcs.w3.org/hg/webdriver/raw-file/tip/webdriver-spec.html#widl-WebElement-isDisplayed-boolean

查看更多
登录 后发表回答